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lorasvet [3.4K]
3 years ago
5

Alguien me ayuda pls

Mathematics
1 answer:
Vesna [10]3 years ago
5 0

(sorry I don't understand your language but, here's my answer)

  • a/12 + 2/3(b) = ?
  • a = 5, b = -4
  • 5/12 + 2/3(-4)
  • 5/12 + 2/-12
  • 1/4

<h2><u>ANSWER:</u></h2>

  • 1/4
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Answer:

Step-by-step explanation:

tan Θ + tan 2Θ + √3 tan Θ tan 2Θ = √3

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tan Θ + tan 2Θ = √3 ( 1 - tan Θ tan 2Θ)

(tan Θ + tan 2Θ) / (1 - tanΘ tan 2Θ) = √3

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3 years ago
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Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

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In every number, set every digit to zero that is not 8. Then look at the question again.

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The appropriate choice is ...

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