Answer:
1.82x10⁻¹⁹Joules is the energy of the photon that is absorbed by the electron.
Explanation:
The energy of a photon is given by the equation:
E = h×ν
<em>Where E is energy of the photon in Joules.</em>
<em>h is Planck's constant (6.6262x10⁻³⁴Js)</em>
<em>And ν is frequency of the photon (In Hz = s⁻¹)</em>
<em />
The frequency of the photon is 2.74x10¹⁴Hz. That means its energy is:
E = 6.6262x10⁻³⁴Js × 2.74x10¹⁴s⁻¹
E =
<h3>1.82x10⁻¹⁹Joules is the energy of the photon that is absorbed by the electron</h3>
<em />
Answer:
Two electrons each!
Explanation:
The question pretty much requires us to find the oxidation number of Zinc in the compound.
Zn3P2
Following oxidation number rules;
O.N of Zn3P2 = 0
.Since phosphorus has valence of 5, it needs three more electrons to achieve its octet state. Hence;
Oxidation number of P = -3
Let oxidation number of Zn = x
We have;
3x + 2 (-3) = 0
3x + (-6) = 0
3x = 6
x = 6/3 = 2
This means each zn electrons lost 2 electrons.
Answer:
defined as a process in which mo heat transfer take place
Explanation:
is a process which occurs without transferring heat /mass between the system and it's surrounding.
