1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kobusy [5.1K]
3 years ago
6

Balance the following chemical equation, then answer the following question.

Chemistry
1 answer:
julsineya [31]3 years ago
3 0
Molar mass:

O2 = 31.99 g/mol
C8H18 = 144.22 g/mol

<span>2 C8H18(g) + 25 O2(g) = 16 CO2(g) + 18 H2O(g)

2 x 144.22 g --------------- 25 x 31.99 g
10.0 g ----------------------?? ( mass of O2)

10.0 x 25 x 31.99 / 2 x 144.22 =

7997.5 / 288.44 => 27.72 g of O2

hope this helps!


</span>

You might be interested in
What is the molarity of 500 ml of a solution containing 85.0g AgNO3? A) 0.5 M B) 1.0 M C) 2.0 M D) 5.0 M
kari74 [83]

Consider the equation for calculating molarity: (no. of mole of solute)÷(volume of solution)

First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass

no. of mole of 85.0g of AgNO3 = 85.0/(107.9+14.0+16.0x3)

=0.5mol

Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.

Volume of solution = 500/1000

= 0.5 dm3

Therefore, the molarity is

0.5/0.5

=1.0M

The answer should be B.

3 0
3 years ago
1. When an element has a positive charge :
natita [175]

Answer:

2) AAAAAA

1)BBBBBBBB

3) I think a or c

8 0
3 years ago
Which of th following is an example of how scientist might use a model?
Gemiola [76]
C. marbles placed inside hollow sphere
8 0
3 years ago
_______________ galaxies range in shape from almost perfect spheres to flattened globes with the light brightest in the center a
Mademuasel [1]
The answer is B: elliptical. Spirals have arms so are not round, no such thing as circular, and irregular don't have simple geometric shapes
6 0
3 years ago
Read 2 more answers
Polonium- 210 , Po210 , decays to lead- 206 , Pb206 , by alpha emission according to the equation Po84210⟶Pb82206+He24 If the ha
elixir [45]

Answer:

0.269 g

Explanation:

Po_{210} ^{84}  ⟶  Pb_{206} ^{82}+  + He_{4} ^{2}

Data:

Half-life of  Po_{210} ^{84}  (T(1/2)) = 138.4 days

Mass of PoCl4 = 561 mg (0,561 g) and molecular weight of PoCl4 = 350. 79 g/mol  

Time = 338.8 days  

Isotopic masses  

Po_{210} ^{84} = 209.98 g/mol  

Pb_{206} ^{82} = 205.97 g/mol  

Concepts  

Avogadro’s number: This is the number of constituent particles that are contained in a mol of any substance. These constituted particles can be atoms, molecules or ions). Its value is 6.023*10^23.  

The radioactive decay law is  

N=Noe^(-λt)

Where:  

No = number of atoms in t=0

N = number of atoms in t=t (now) in this case t=338.8 days  

λ= radioactive decay constant  

The radioactive constant is related to the half-life by the next equation  

λ= \frac{ln 2}{t(1/2)}

so  

λ= \frac{ln2}{138.4 days}  =0,005008 days^(-1)

No (Atoms of  Po_{210} ^{84}  in t=0)

To get No we need to calculate the number of atoms of  Po_{210} ^{84}   in the initial sample. We have a sample of 0,561 g of PoCl4. If we get the number of moles of PoCl4 in the sample, this will be the number of moles of  Po_{210} ^{84}  in the initial sample.  

This is:

\frac{0,561 g of PoCl4}{350. 79 g of PoCl4 /mol} = 0,001599 mol of  PoCl4

This is the number of mol of  Po_{210} ^{84} in the initial sample.

To get the number of atoms in the initial sample we use the Avogadro’s number = 6.023*10^23  

0,001599 mol of  Po_{210} ^{84} * 6.023*10^23 atoms/ mol of  Po_{210} ^{84} = 9.632 *10^20 atoms of  Po_{210} ^{84}

Atoms after 338.8 days

We use the radioactive decay law to get this value  

N=Noe^(-λt)

N=9.632*10^20 e^(-0,005008 days^(-1) * 338.8 days) =1.765*10^20

This is the number of atoms of  Po_{210} ^{84} in the sample after 338.8 days has passed  

The number of atoms  Po_{210} ^{84} transformed is equal to the number of atoms of Pb_{206} ^{82}  produced.  

The number of atoms of Po_{210} ^{84} transformed is No - N  

9.632 *10^20 – 1.765 *10^20 = 7.866*10^20

So, 7.866*10^20 is the number of atoms of Pb_{206} ^{82} produced  

We can get the mass with the Avogadro’s number

(7.866*10^20 atoms of Pb_{206} ^{82} ) / ( 6.023*10^23 atoms of Pb_{206} ^{82} / mol of Pb_{206} ^{82} =  0.001306 moles of Pb_{206} ^{82}

This number of moles have a mass of:

(0,001306 moles of Pb_{206} ^{82} )* (205.97 g of Pb_{206} ^{82} /mol of Pb_{206} ^{82} ) = 0.269 g  

3 0
3 years ago
Other questions:
  • What does your circulatory system transport??
    14·2 answers
  • Write the empirical formula for C6H6
    14·2 answers
  • Which of the following is an example of a behavioral adaptation
    7·2 answers
  • For a given reaction, adding a catalyst increases the rate of the reaction by
    9·2 answers
  • How to assign oxidation and reduction numbers
    15·1 answer
  • T or F: The mass of a neutron is so small that it is rounded to 1 amu.
    8·2 answers
  • The fossils in line 4 __ are the ones in line 1
    12·2 answers
  • Please help....thank you
    11·1 answer
  • URGENT A gas occupies a volume of 2.4 L at 0.14 ATM. What volume will the gas occupy at 0.84 ATM ?
    9·1 answer
  • The molar mass of carbon dioxide is 44.0 g/mol. How many moles of CO2 are present in a 58.4 gram sample of CO2
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!