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MaRussiya [10]
3 years ago
7

A photon of light with a frequency of 2.74 x 1014 Hz collides with an electron. How much energy

Chemistry
1 answer:
sesenic [268]3 years ago
4 0

Answer:

1.82x10⁻¹⁹Joules is the energy of the photon that is absorbed by the electron.

Explanation:

The energy of a photon is given by the equation:

E = h×ν

<em>Where E is energy of the photon in Joules.</em>

<em>h is Planck's constant (6.6262x10⁻³⁴Js)</em>

<em>And ν is frequency of the photon (In Hz = s⁻¹)</em>

<em />

The frequency of the photon is 2.74x10¹⁴Hz. That means its energy is:

E = 6.6262x10⁻³⁴Js × 2.74x10¹⁴s⁻¹

E =

<h3>1.82x10⁻¹⁹Joules is the energy of the photon that is absorbed by the electron</h3>

<em />

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