Question

A photon of light with a frequency of 2.74 x 1014 Hz collides with an electron. How much energy

Answer 1

Answer:

1.82x10⁻¹⁹Joules is the energy of the photon that is absorbed by the electron.

Explanation:

The energy of a photon is given by the equation:

E = h×ν

Where E is energy of the photon in Joules.

h is Planck's constant (6.6262x10⁻³⁴Js)

And ν is frequency of the photon (In Hz = s⁻¹)

The frequency of the photon is 2.74x10¹⁴Hz. That means its energy is:

E = 6.6262x10⁻³⁴Js × 2.74x10¹⁴s⁻¹

E =

1.82x10⁻¹⁹Joules is the energy of the photon that is absorbed by the electron