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Sloan [31]
3 years ago
14

PLEASE HELP Let f(x)=-4x+7 and g(x)=10x-6. Find f(g(x)) Answer choices: A. -40x+24 B. -40x+31 C. -40x+64 D. -40x+70

Mathematics
1 answer:
serg [7]3 years ago
8 0
f(x)=-4x+7 \\  \\ g(x)=10x-6 \\  \\ f(g(x))=f(10x-6)=-4*(10x-6)+7=-40x+24+7= \\  \\ -40x+31

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A sample of 66 obese adults was put on a low-carb diet for a year. The average weight loss was 11 pounds and the standard deviat
Illusion [34]

Answer:

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{19}{\sqrt{66}} = 6.02

The lower end of the interval is the sample mean subtracted by M. So it is 11 - 6.02 = 3.98 pounds

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

7 0
3 years ago
Read 2 more answers
Need some help, kinda stuck
ElenaW [278]

Answer:

7/4

Step-by-step explanation:

\displaystyle\frac{2 +  \sqrt{ - 3} }{2} ( \frac{2 -  \sqrt{ - 3} }{2} )~~~~~~

Evaluate.

Solution:

Rewrite it as,

  • \displaystyle\frac{2 +    \sqrt{  - 1 }  \sqrt{  3} }{2} ( \frac{2 -  \sqrt{ - 1}  \sqrt{3} }{2} )
  • \displaystyle\frac{2 +  i\sqrt{  3} }{2} ( \frac{2 -  i\sqrt{ 3} }{2} )~~~~~~

Multiplying them,

  • \displaystyle\frac{(2 +  i\sqrt{  3})\times(2 - i \sqrt{3})   }{2 \times 2}

  • \displaystyle\frac{(2 +  i\sqrt{  3})\times(2 - i \sqrt{3})   }{4}

Applying Distributive property,

  • \displaystyle\frac{2(2 +  i\sqrt{  3}) +  \: i \sqrt{3} (2 - i \sqrt{3})   }{4}

  • \cfrac{2 \times 2 + 2( - i \sqrt{3} ) + i \sqrt{3}(2 - i \sqrt{3} ) }{4}

  • \cfrac{2 \times 2 + 2( - i \sqrt{3}) + i \sqrt{3}   \times 2 + i \sqrt{3} ( - i \sqrt{3}) }{4}

Combining each terms,

  • \cfrac{4 - 2i \sqrt{3} + 2i \sqrt{3}   + 3}{4}
  • \cfrac{ - 2i \sqrt{3}  + 2i \sqrt{3} + 7 }{4}
  • \boxed{\cfrac{ 7}{4} }

Last Choice is accurate.

7 0
2 years ago
Read 2 more answers
Please help thanks this is due today!
kondaur [170]

D. ({ - 8})^{2}  - 9 + ( - 7) ✅

Step-by-step explanation:

{( - 32 \div4 })^{2}  - 9 + ( - 7) \\  \\  =  ({ - 8})^{2}  - 9 +(- 7 )\\  \\=64-9-7\\\\  = 64 - 16 \\  \\  = 48

<u>Note</u>:-

\sf\red{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\sf\red{(+\:x\:-)\:=\:-}

\sf\red{(-\:x\:-)\:=\:+}

\bold{ \green{ \star{ \orange{Mystique35}}}}⋆

7 0
3 years ago
Jack has 3 red sweets, 2 blue sweets and 4 green sweets, he takes one at random and eats it, he then takes another one, what is
Roman55 [17]
Um.....yes
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6 0
3 years ago
Find MO and PR <br> ............................................................
ddd [48]

MO = 12 and PR = 3

Solution:

Given \triangle M N O \sim \Delta P Q R.

Perimeter of ΔMNO = 48

Perimeter of ΔPQR = 12

MO = 12x and PR = x + 2

<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>

$\Rightarrow \frac{\text{Perimeter of }\triangle MNO}{\text{Perimeter of }\triangle PQR} =\frac{MO}{PR}

$\Rightarrow \frac{48}{12} =\frac{12x}{x+2}

Do cross multiplication.

$\Rightarrow 48({x+2})= 12(12x)

$\Rightarrow 48x+96= 144x

Subtract 48x from both sides.

$\Rightarrow 48x+96-48x= 144x-48x

$\Rightarrow 96= 96x

Divide by 96 on both sides, we get

⇒ 1 = x

⇒ x = 1

Substitute x = 1 in MO an PR.

MO = 12(1) = 12

PR = 1 + 2 = 3

Therefore MO = 12 and PR = 3.

7 0
3 years ago
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