Alex wants to buy 7 DVDs.

Darrel has 36 daisies and 54 roses. He wants to put an equal number of daisies and roses into vases. What is the GREATEST number

castortr0y [4]

Answer:

18 number of daisies and 18 number of roses

Step-by-step explanation:

We are told Darrel has 36 daisies and 54 roses.

And that He wants to put an equal number of daisies and roses into vases.

To get the equal number, it means we have to find the greatest common factor of 36 and 54.

Factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18, 36

Factors of 54 = 1, 2, 3, 6, 9, 18, 27, 54

From the factors of both 36 and 54, the greatest common factor to both of them is 18.

Thus, the GREATEST number of daisies and roses Darrel can put in each vase is 18 each

5 0

3 years ago

Value of the pronumeral and describe the rule. 4,1,-2,p,-8,-11

Citrus2011 [14]

Answer:

p = -5

every element in the sequence is created by subtracting 3 from the pervious element.

Step-by-step explanation:

I am not sure you put every necessary information here.

but I'd the visible information is truly everything, then it's is trivial.

the difference between 4 and 1 is ... well, -3. meaning we subtract 3 from 4 to get 1.

we suspect this is the rule and keep trying.

1 -3 = -2

hey it works.

and -8 -3 = -11

hey, also correct.

and the difference between -2 and -8 is -6, and when we place another item in between (p), we cut that in half again to -3. so, it is all consistent.

therefore,

p = -2 -3 = -5

the rule is

an = an-1 - 3

6 0

3 years ago

What is the lowest common factor of 5 and 9

neonofarm [45]

Answer:

534

Step-by-step explanatio

lol

4 0

2 years ago

If f(x) = 3x - 12, what is f(2)? O A. -18 O B. -6 O c. 6 O D. 18

zhannawk [14.2K]

Replace x with 2:

f(x) = 3x -12:

f(2) = 3(2) - 12

= 6 - 12

= -6

3 0

3 years ago

Read 2 more answers

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$