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WARRIOR [948]
3 years ago
6

A pendulum on a grandfather clock

Physics
1 answer:
egoroff_w [7]3 years ago
5 0
4.0 ilynits per second Alaskan es muy du facial in the oscillates 1.99
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What is one way that an electric field is different from a magnetic field?
wel

Answer:

The one of the major difference between the magnetic and electric field is that the electric field induces around the static charge particle which is either negative or positive, whereas the magnetic field produces around the poles (i.e., the north and south pole) of the magnet

Explanation:

4 0
3 years ago
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Use the definition of scalar product, a with arrow · b with arrow = ab cos θ, and the fact that a with arrow · b with arrow = ax
Zolol [24]

Answer:

5+5=10

4+6=10

angle between is 45

3 0
3 years ago
If the mass of the body is doubled what should be its speed so as to maintain the same kinetic energy ?​
soldier1979 [14.2K]

Answer:

The speed should be reduced by 1/√2 or 0.707 times

Explanation:

The relationship between the kinetic energy, mass and velocity can be represented by the following equation:

K.E = ½m.v²

In this equation, the mass is inversely proportional to the square of the velocity or speed. This means that as the mass increases, the speed reduces by × 2.

Let; initial mass = m1

Final mass = m2

Initial velocity = v1

Final velocity = v2

According to the question, if the mass of the body is doubled i.e. m2 = 2m

½m1v1² = ½m2v2²

½ × m × v1² = ½ × 2m × v2²

Multiply both sides by 2

(½ × m × v1²)2 = (½ × 2m × v2²)2

m × v1² = 2m × v2²

Divide both sides by m

v1² = 2v2²

Divide both sides by 2

v1²/2= v2²

Square root both sides

√v1²/2= √v2²

v1/√2 = v2

v2 = 1/√2 v1

This shows that to maintain the same kinetic energy if the mass is doubled, the speed should be reduced by 1/√2 or 0.707 times.

8 0
2 years ago
The process of testing a hypothesis by collecting data is called
deff fn [24]
I think it’s the scientific method
7 0
3 years ago
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I need to know the solution and the formula.
scoray [572]

<u>Statement</u><u>:</u>

A non-deformed spring is 15 cm long. When a 2.0 N force is applied to it, its length becomes 19 cm.

<u>To </u><u>find </u><u>out:</u>

The spring constant of the spring.

<u>Solution:</u>

  • Force (F) = 2 N

  • Extension of the spring (x)
  • = (19 - 15) cm
  • = 4 cm
  • = 0.04 m [since we have to find the answer in N/m]

  • Let the spring constant of the spring be k.

  • We know, the formula of spring force, i.e.,
  • F = kx

  • Putting the values in the above formula, we get
  • 2 N = k × 0.04 m
  • or, k = 2 N ÷ 0.04 m
  • or, k = 50 N/m

<u>Answer</u><u>:</u>

<u>The </u><u>spring </u><u>constant</u><u> of</u><u> </u><u>this </u><u>spring </u><u>is </u><u>5</u><u>0</u><u> </u><u>N/</u><u>m.</u>

Hope you could understand.

If you have any query, feel free to ask.

7 0
2 years ago
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