Mayan kings and many school sports teams are named for the puma, cougar, or mountain lion felis concolor, the best jumper among
animals. it can jump to a height of 13.8 ft when leaving the ground at an angle of 42.2°. with what speed, in si units, does it leave the ground to make this leap?
To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation: vi^2 - vf^2 = 2*g*h Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi: vi^2 = 29.72 ft/s This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle: 29.72 ft/s = (v_original)*(sin 42.2<span>°</span>) v_original = 44.24 ft/s Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.
Explanation:the voltage is just like the force that drives the current through out the circui... When trippled, the force increases and the current increases since the resistance in the circuit remains constant.
