Question

I need to know the solution and the formula.

Answer 1

Statement:

A non-deformed spring is 15 cm long. When a 2.0 N force is applied to it, its length becomes 19 cm.

To find out:

The spring constant of the spring.

Solution:

• Force (F) = 2 N

• Extension of the spring (x)
• = (19 - 15) cm
• = 4 cm
• = 0.04 m [since we have to find the answer in N/m]

• Let the spring constant of the spring be k.

• We know, the formula of spring force, i.e.,
• F = kx

• Putting the values in the above formula, we get
• 2 N = k × 0.04 m
• or, k = 2 N ÷ 0.04 m
• or, k = 50 N/m

Answer:

The spring constant of this spring is 50 N/m.

Hope you could understand.

If you have any query, feel free to ask.