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2 years ago

I need to know the solution and the formula.

Physics

1 answer:

scoray [572]2 years ago

7 0

Statement:

A non-deformed spring is 15 cm long. When a 2.0 N force is applied to it, its length becomes 19 cm.

To find out:

The spring constant of the spring.

Solution:

Force (F) = 2 N

Extension of the spring (x)
= (19 - 15) cm
= 4 cm
= 0.04 m [since we have to find the answer in N/m]

Let the spring constant of the spring be k.

We know, the formula of spring force, i.e.,
F = kx

Putting the values in the above formula, we get
2 N = k × 0.04 m
or, k = 2 N ÷ 0.04 m
or, k = 50 N/m

Answer:

The spring constant of this spring is 50 N/m.

Hope you could understand.

If you have any query, feel free to ask.

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