B because 2800 divide by 40 is 20
The largest value of current that the breaker can carry = Imax=35.4A
Explanation:
Rms value of current= Irms= 25 A
The rms current and the maximum current are related as
Imax= √2 Irms
Imax=√2 (25)
Imax=35.4 A
Thus the maximum current carried by the breaker= 35.4 A
Answer:
Final volume, V2 = 24.62 L
Explanation:
Given the following data;
Initial volume = 40 L
Initial pressure = 80 Pa
Final pressure = 130 Pa
To find the final volume V2, we would use Boyles' law.
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
Substituting into the equation, we have;
![80 * 40 = 130V_{2}](https://tex.z-dn.net/?f=%2080%20%2A%2040%20%3D%20130V_%7B2%7D%20)
![3200 = 130V_{2}](https://tex.z-dn.net/?f=%203200%20%3D%20130V_%7B2%7D%20)
![V_{2} = \frac {3200}{130}](https://tex.z-dn.net/?f=%20V_%7B2%7D%20%3D%20%5Cfrac%20%7B3200%7D%7B130%7D)
![V_{2} = 24.62](https://tex.z-dn.net/?f=%20V_%7B2%7D%20%3D%2024.62%20)
Final volume, V2 = 24.62 Liters
Answer:
a) ![F=1.044\times 10^9\ N](https://tex.z-dn.net/?f=F%3D1.044%5Ctimes%2010%5E9%5C%20N)
b)![F'=1.044\times 10^9\ N](https://tex.z-dn.net/?f=F%27%3D1.044%5Ctimes%2010%5E9%5C%20N)
c) ![F_p=1.0672\times10^{-7}\ N](https://tex.z-dn.net/?f=F_p%3D1.0672%5Ctimes10%5E%7B-7%7D%5C%20N)
d) Treat the humans as though they were points or uniform-density spheres.
Explanation:
Given:
- mass of Mars,
![M=6.4\times 10^{23}\ kg](https://tex.z-dn.net/?f=M%3D6.4%5Ctimes%2010%5E%7B23%7D%5C%20kg)
- radius of the Mars,
![r=3.4\times 10^{6}\ m](https://tex.z-dn.net/?f=r%3D3.4%5Ctimes%2010%5E%7B6%7D%5C%20m)
- mass of human,
![m=80\ kg](https://tex.z-dn.net/?f=m%3D80%5C%20kg)
a)
Gravitation force exerted by the Mars on the human body:
![F=G.\frac{M.m}{r^2}](https://tex.z-dn.net/?f=F%3DG.%5Cfrac%7BM.m%7D%7Br%5E2%7D)
where:
= gravitational constant
![F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}](https://tex.z-dn.net/?f=F%3D6.67%5Ctimes10%5E%7B-11%7D%5Ctimes%20%5Cfrac%7B6.4%5Ctimes%2010%5E%7B23%7D%5Ctimes%2080%7D%7B%283.4%5Ctimes%2010%5E%7B6%7D%29%5E2%7D)
![F=1.044\times 10^9\ N](https://tex.z-dn.net/?f=F%3D1.044%5Ctimes%2010%5E9%5C%20N)
b)
The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.
![F'=F](https://tex.z-dn.net/?f=F%27%3DF)
![F'=1.044\times 10^9\ N](https://tex.z-dn.net/?f=F%27%3D1.044%5Ctimes%2010%5E9%5C%20N)
c)
When a similar person of the same mass is standing at a distance of 4 meters:
![F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}](https://tex.z-dn.net/?f=F_p%3D6.67%5Ctimes10%5E%7B-11%7D%5Ctimes%20%5Cfrac%7B80%5Ctimes%2080%7D%7B4%7D)
![F_p=1.0672\times10^{-7}\ N](https://tex.z-dn.net/?f=F_p%3D1.0672%5Ctimes10%5E%7B-7%7D%5C%20N)
d)
The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.
- Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
- Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.