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3 years ago

Calculate the average value of an AC signal with a peak amplitude of 10V and a frequency of 10 kHz.

Physics

1 answer:

Solnce55 [7]3 years ago

3 0

Answer:

V(average)=6.37 V

Explanation:

Given Data

Peak Voltage=10V

Frequency=10 kHZ

To Find

Average Voltage

Solution

For this first we need to find Voltage peak to peak

Voltage (peak to peak)= 2× voltage peak

Voltage (peak to peak)= 2×10

Voltage (peak to peak)= 20 V

Now from Voltage (peak to peak) formula we can find the Average Voltage

Voltage (peak to peak)=π×V(average)

V(average)=Voltage (peak to peak)/π

V(average)=20/3.14

V(average)=6.37 V

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3 years ago

What type of energy does a spinning turbine have?

Alenkasestr [34]

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3 years ago

The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron

FrozenT [24]

Answer:

Speed of the electron is 2.46 x 10^8 m/s

Explanation:

momentum of the electron before relativistic effect = $M_{0} V$

where $M_{0}$ is the rest mass of the electron

V is the velocity of the electron.

under relativistic effect, the mass increases.

under relativistic effect, the new mass M will be

M = $M_{0}/ \sqrt{1 - \beta ^{2} }$

where

$\beta = V/c$

c is the speed of light = 3 x 10^8 m/s

V is the speed with which the electron travels.

The new momentum will therefore be

==> $M_{0}V/ \sqrt{1 - \beta ^{2} }$

It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have

1.75 $M_{0} V$ = $M_{0}V/ \sqrt{1 - \beta ^{2} }$

the equation reduces to

1.75 = $1/ \sqrt{1 - \beta ^{2} }$

square both sides of the equation, we have

3.0625 = 1/ $(1 - \beta ^{2} )$

3.0625 - 3.0625 $\beta ^{2}$ = 1

2.0625 = 3.0625 $\beta ^{2}$

$\beta ^{2}$ = 0.67

β = 0.819

substitute for $\beta = V/c$

V/c = 0.819

V = c x 0.819

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6 0

3 years ago

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Lana71 [14]

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3 years ago

Read 2 more answers

A force of 6.0 N gives a 2.0 kg block an acceleration of 3.0

Semenov [28]

Explanation:

The Net Force of the object can be written by:

Fnet = ma

where m is the mass of the object in kg

a is the acceleration of the object in m/s^2

Hence by applying the formula we get:

Fnet = (2.0)(3.0)

= 6N

We also know that Net force is also the sum of all forces acting on an object. In this case Friction and the Pushing Force is acting on the object. Hence we can write that:

Fnet = Pushing Force + (-Friction)

6N = 6N - Friction

Friction = 0N

Hence the force of friction is 0N.

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3 years ago