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aleksandr82 [10.1K]
3 years ago
7

Calculate the amount of work done (in joules) to raise the 0.2kg mass 0.5 m

Physics
1 answer:
Alex Ar [27]3 years ago
8 0

Answer:

1

Explanation:

A=mgh=0.2*10*0.5=1 J

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Find the angle (above the horizontal) at which a projectile achieves its maximum range, if y=y0.
KatRina [158]
The answer is 45 degrees. 
According to the Kinematics of projectile motion, if the purpose is to maximize range, optimum angle of landing is always 45 degrees.If the purpose is to maximize range & projection height is zero, the optimum angle of projection (and landing) is 45 degrees.
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3 years ago
A car traveling initially at 7.35 m/s acceler-
Flura [38]

Answer:

v_f=9,07~m/s

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes uniformly in time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

v_f=v_o+at

The car initially travels at vo=7.35 m/s and accelerates at a rate of a=0.824~m/s^2 during t=2.09 s.

The final velocity is:

v_f=7.35+0.824*2.09

\mathbf{v_f=9,07~m/s}

4 0
3 years ago
7. A ball of mass m makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.450 its
emmasim [6.3K]

Answer:

mass of the second ball is 0.379m

Explanation:

Given;

mass of first ball = m

let initial velocity of first ball = u₁

let final velocity of first ball  = v₁ = 0.45u₁

let the mass of the second ball = m₂

initial velocity of the second ball, u₂ = 0

let the final velocity of the second ball = v₂

Apply the principle of conservation of linear momentum;

mu₁ + m₂u₂ = mv₁ + m₂v₂

mu₁  +  0  = 0.45u₁m + m₂v₂

mu₁  = 0.45u₁m + m₂v₂ -------- equation (i)

Velocity for elastic collision in one dimension;

u₁ + v₁ = u₂ + v₂

u₁ + 0.45u₁ = 0 + v₂

1.45u₁ = v₂ (final velocity of the second ball)

Substitute in v₂ into equation (i)

mu₁  = 0.45u₁m + m₂(1.45u₁)

mu₁ = 0.45u₁m + 1.45m₂u₁

mu₁ - 0.45u₁m = 1.45m₂u₁

0.55mu₁ = 1.45m₂u₁

divide both sides by u₁

0.55m = 1.45m₂

m₂ = 0.55m / 1.45

m₂ = 0.379m

Therefore, mass of the second ball is 0.379m (where m is mass of the first ball)

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Which is the best location for storing radioactive wastes?
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The answer is in chambers carved into the rock of a mountain<span>. Radioactive waste should be well disposed where they are little to no anthropogenic activity that would uncover them. </span><span>This is especially critical for high-level radioactive waste should be buried deep up to 2000 meters. While low-level radioactive waste can be buried 100 meters into the ground such as in sand, the risk is that it could contaminate the water table.</span>






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4 years ago
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Which of the following is not in the form of waves?
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C. Seismic energy
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