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aleksandr82 [10.1K]
2 years ago
7

Calculate the amount of work done (in joules) to raise the 0.2kg mass 0.5 m

Physics
1 answer:
Alex Ar [27]2 years ago
8 0

Answer:

1

Explanation:

A=mgh=0.2*10*0.5=1 J

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An industrial firm has two electrical loads connected in parallel across the power source. Power is supplied to the firm at 4000
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Answer:

I = 27.65A < 40.59°

PowerFactor = 0.76

Explanation:

Current on the heating load is:

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Current on the inductive load:

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The sum of both currents is:

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m1*g*h2-\frac{m1*V_{B'}^2}{2}=0 Solving for h2:

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