All categories

3 years ago

6x-7y= -2 please help me

Mathematics

1 answer:

Nana76 [90]3 years ago

6 0

Answer:

X=7/6y+-1/3

Step-by-step explanation:

It will be hard for me to demonstrate the equation

You might be interested in

3x²+2x²+x-2 divided x+2

ICE Princess25 [194]

Answer:

3x^2-4x+9 remainder -20/x+2

Step-by-step explanation:

7 0

3 years ago

Solve this equation <br> ÷2(1+2)

nasty-shy [4]

The answer is 6 because you add the 1 and the 2 first and then multiple to get 6. I don’t know why you put the division sign in front of the 2 though.

6 0

3 years ago

Read 2 more answers

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

3 years ago

I have a 84% in class, there is a 25 point quiz worth 100 points, how what grade do I need to get to at least have an average gr

Thepotemich [5.8K]

At least about 20 points it can depend on the class but not really.

4 0

3 years ago

Read 2 more answers

HEEEEEEELP ASAP Janette went to Tire Mart and paid $122.57 per tire for 4 tires and a flat rate fee for installation for a total

Oduvanchick [21]

$122.57 • 4 + $555.28 = $1,045.56

$136.71 • 4 + $585.34 = $1,132.18

$1,132.18 - $1,045.56 = $86.62

6 0

3 years ago