Answer:
There will be produced 3.5 moles of oxygen (O2)
Explanation:
Step 1: Data given
Number of moles Mercury (II) oxide (HgO) = 7 moles
Step 2: The balanced equation
2HgO → O2 + 2Hg
Step 3: Calculate number of moles of O2
For 2 moles of Mercury (II) oxide (HgO) we produce 1 mol of O2 and 2 moles of Hg
For 7 moles of Mercury (II) oxide (HgO) we'll have 7/2 = 3.5 moles of O2
There will be produced 3.5 moles of oxygen (O2)
Answer:
the acceleration i think is 10
Explanation:
5x10=50
We are given with
<span>ΔHo = 38.0 kJ
ΔSo = 112.9
for these standard conditions:
To = 25 C
Po = 1 atm
Using the Clapeyron Equation
ln (P/Po) = (</span><span>ΔHo / R)(1/T1 - 1/T2)
Substitute the values and solve for P (Temperature should be in Kelvin)</span>
The units of mass can be Fran or kilogram
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