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FinnZ [79.3K]
3 years ago
10

20 points to whoever can answer these 3 questions correctly

Chemistry
1 answer:
Mkey [24]3 years ago
8 0

Answer:

1) A. NO

2) B. 4

3) D. 8

Explanation:

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what is the pH of a solution prepared from solid, neutral 2-nitrophenol providing a fromal concentration of 0.0353M, given that
REY [17]

Answer:

pH = 4.34

Explanation:

pH= -1/2(logKa) -1/2(log C)

= -1/2( log 5.98*10^-8) -1/2(log 0.0353)

=-1/2(-7.22)-1/2(-1.45)

=3.61+0.725= 4.34

7 0
3 years ago
Hello I'm here looking for help while if u can then help me I lost all my points just posting answers but please help with this
Evgen [1.6K]

Answer:

Trying to find out the answer

Explanation:

Please mark me as brainlist.

6 0
4 years ago
Insoluble molecular compounds break apart into atoms when added to water.<br> True<br> O False
masha68 [24]

Answer:

False.

This is false because, no chemical reaction could possibly happen.

But in case of sodium it is highly reactive with water.......... so there will be a chemical reaction.

but as sodium is not a insoluble molecular compound this is not applicable to the situation.

8 0
3 years ago
Why is science boring
murzikaleks [220]

Answer:

cuz what we are shown in school often fails to foster curiosity in us.

Explanation:

7 0
2 years ago
Read 2 more answers
1 C3H8 + 5 O2 --&gt; 3 CO2 + 4H20. If 1.5 moles of C3H8 react, how many
UNO [17]

Answer:

First confirm the reaction is balanced:

C3H8 + 5O2 --> 3CO2 + 4H20 (3 cabon - check; 8 hydrogen - check; 10 oxygen - check).

a) In the equation there is a 5:1 ratio between propane and oxygen.  We also know that number of mole is proportional to pressure and volume.  Since pressure is constant (STP) then the volume of O2 is 7.2 * 5 = 36 litres.

b) For a near ideal gas that PV = nRT (combined gas law).  So for 7.2 litres propane we find n(propane) = 101.3 * 7.2/8.314*298 ~ 0.29 mole (using metric units throughout for simplicity).

There is a 1:3 ratio between propane and CO2.  Therefore 3 * 0.29 = 0.87 mole of CO2 is produced.

MW(CO2) ~ 44 g/mol.  Therefore m(CO2) = 44 * 0.87 ~ 38.3 g

c) We know we need more oxygen than propane (due to the 1:5 ratio) so oxygen is the limiting reagent.  Again Volume is proportional to number of mole and we see there is a 5:4 ratio between oxygen and water.  Therefore the volume of water vapour produced will be (4/5) * 15 = 12 litres.

The other questions use the same technique and will give you some much needed practice.

Explanation:

7 0
4 years ago
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