A homogeneous mixture<span> has the same uniform appearance and composition throughout. Many </span>homogeneous mixtures<span> are commonly referred to as solutions. A </span>heterogeneous mixture <span>consists of visibly </span>different<span> substances or phases. The three phases or states of matter are gas, liquid, and solid. Now this is my answer. So revise it a little. You dont want plagiarism </span>
Answer:
Procedure (2)
Explanation:
Assume the dialyses come to equilibrium in the allotted times.
Procedure (1)
If you are dialyzing 5 mL of sample against 4 L of water, the concentration of NaCl will be decreased by a factor of
Procedure (2)
For the first dialysis, the factor is
After a second dialysis, the original concentration of NaCl will be reduced by a factor of
Procedure (2) is more efficient by a factor of
Answer:
E. just before it reaches the ground.
Explanation:
The "kinetic energy" refers to the energy<em> when an object moves or is in motion.</em> When the ball leaves the racket, it is considered to have a great amount of kinetic energy. However, this decreases as the ball reaches its maximum height, but the potential energy is at its highest. Upon falling down, its kinetic energy increases but its potential energy decreases.
<em>Provided that there's no air resistance,</em><em> the speed of falling is even faster for the ball because of gravity and nothing is slowing it down, </em>which means it will have a<u> maximum kinetic energy</u><u> just before it reaches the ground.</u>
Answer:
f = 7.5 E14 s-1
Explanation:
energy emitted by photon:
- E = h.c / λ.......(1)
- E = h.f......(2) Planck-Einstein
∴ λ = (400nm)(m/1 E9 nm) = 4.00 E-7 m
∴ h ( Planck's constant) = 6.626070150 E-34 J.s
∴ c (velocity of light) = 3.00 E8 m/s
∴ f (frequency): photon/s
If (1) = (2):
⇒ f = c / λ = E / h
⇒ f = (3.0 E8 m/s) / ( 4.00 E-7 m) = 7.5 E14 s-1
Almost without exceptions, the alkali metals (Li, K, Na,...) are in oxidation state (I) and the alkaline earth metals (Be, Mg, Ca, ...) are in oxidation state (II).
So without confusion, the naming of the metal part is simply the metal name, such as calcium oxide.
The Stock system (which indicates the oxidation state) is required only when the metal exhibits multiple oxidation states, such as iron (II) oxide or iron (III) oxide.
Then again, older nomenclature applies the ending -ous to the lower oxidation state, and -ic to the higher. Using the Latin name ferrum for iron, the previous compounds were named ferrous oxide and ferric oxide respectively.
