15
If it’s not message me I’ll give u the answer
Try adding 11, 11 times. It is a long process, but it should give you what you are looking for. First. to break it down add 10 eleven time, then after you get 110 add the remaining 11.
Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
Answer:
5/6 OR 0.83 (with the three repeating)
Hope that helps!
Step-by-step explanation: