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3 years ago

Graph (-3, 2) (5, 2) (5, -3) and (-3, -3) and find the perimeter.

2 answers:

6 0

The answer is 26. I got this answer by plotting out the points on a coordinate plane and counting the perimeter around the shape to get 26. Hope this helps! :)

Nostrana [21]3 years ago

3 0

Answer:

Step-by-step explanation:

Firstly, plot the points on graph paper which you can find on the internet. The first number in the ordered pair, (the ones in parenthesis), is the x coordinate. The other number is the y coordinate. Put these onto a graph which is attached. The perimeter is 26.

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Anyone nervous about semester exams

Veronika [31]

Answer:

YES

Step-by-step explanation:

I am literally trying to fit in as much studying as possible but I keep getting distracted ;-;

8 0

3 years ago

Michael cuts a piece of wood for a project. The first cut is shown and can be represented by the equation . The second cut needs

Verdich [7]

Short Answer: A
Remark
The second cut is going to have the same slope as the original line. The lines are parallel.

Step One
You need to find the slope. That is the main part of this problem. You can pick any 2 points on the graph to do that.

Point one
(- 11, 10) That point is on the upper left of the line

Point Two
The y intercept is a handy point in this question. It is right on the y axis. Each square counts as 2, so it is at (0,6)

Formula
slope = m = (y2 - y1) / (x2 - x1)

Givens
y2 = 10
y1 = 6
x2 = -12 Each square counts as 2 in the x direction.
x1 = 0

Substitute and solve.
m = (10 - 6) / (-12 - 0)
m = 4/ - 12
m = - 1/3

Step Two
Find the y intercept of the new line using the given point.

So far what we have is
y = (-1/3)x + b
The point used for the second line is (0,-2)
-2 = (-1/3)*0 + b
b = - 2

Answer
The second line is
y = (-1/3)x - 2

8 0

4 years ago

Two dice are tossed. Find the probability of getting the sum of the

pogonyaev

Answer:

Step-by-step explanation:

If you are talking about a die with 6 faces, then 16 isn't possible. 12 is the highest possible number.

If you are talking about some other kind of die, you have to specify it.

I'm going to assume you made a mistake and meant 6.

There are 5 ways to get six

3 - 3

4 - 2

2 - 4

5 - 1

1 - 5

There are 36 ways of throwing 2 dice.

So the probability = 5/36 = 0.1389

If you really did mean 16 then the probability = 0

3 0

3 years ago

The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.What is

Lesechka [4]

Answer:

a) The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

Step-by-step explanation:

Given : The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.

To find : What is the probability that

(a) the total gross sales over the next 2 weeks exceeds $5000;

(b) weekly sales exceed $2000 in at least 2 of the next 3 weeks? What independence assumptions have you made?

Solution :

Let $X_1$ and $X_2$ denote the sales during week 1 and 2 respectively.

a) Let $X=X_1+X_2$

Assuming that $X_1$ and $X_2$ follows same distribution with same mean and deviation.

$E(X)=E(X_1+X_2)=E(X_1)+E(X_2)$

$E(X)=2\mu = 2(220)=4400$

$\sigma_X=\sqrt{var(X_1+X_2)}$

$\sigma_X=\sqrt{2\sigma^2}$

$\sigma_X=\sqrt{2}\sigma$

$\sigma_X=230\sqrt{2}$

So, $X\sim N(4400,230\sqrt{2})$

$P(X>5000)=1-P(X\leq5000)$

$P(X>5000)=1-P(Z\leq\frac{5000-4400}{230\sqrt{2}})$

$P(X>5000)=1-P(Z\leq1.844)$

$P(X>5000)=1-0.967$

$P(X>5000)=0.0321$

The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The probability that sales exceed teh 2000 and amount in at least 2 and 3 next week.

We use binomial distribution with n=3.

$P(X>2000)=1-P(X\leq2000)$

$P(X>2000)=1-P(Z\leq\frac{2000-2200}{230})$

$P(X>2000)=1-P(Z\leq-0.87)$

$P(X>2000)=1-0.1922$

$P(X>2000)=0.808$

Let Y be the number of weeks in which sales exceed 2000.

Now, $P(Y\geq 2)$

So, $P(Y\geq 2)=P(Y=2)+P(Y=3)$

$P(Y\geq 2)=^3C_2(0.8077)^2\cdot (1-0.8077)+^3C_3(0.8077)^3$

$P(Y\geq 2)=0.37635+0.52692$

$P(Y\geq 2)=0.90327$

The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

3 0

3 years ago

Please help asap!!!!!!!!!!!!

tatuchka [14]

Your answer is C - 50.

Hope this helps.

3 0

3 years ago

Read 2 more answers