1) first, we have to convert the grams to moles of AuCl3 using the molar mass of the molecule.
molar mass of AuCl3= 197 + (35.5 x 3)= 303.5 g/mol
73.4 g (1 mol AuCl3/ 303.5 g)= 0.242 moles
2) now. let's convert moles of AuCl3 to moles of chlorine gas (Cl2) using the mole-mole ratio
0.242 mol AuCl3 (3 mol Cl2/ 2 mol AuCl3)= 0.363 mol Cl2
3) finally, we convert moles to grams using the molar mass of Cl2.
molar mass of Cl2 = 35.5 x 2= 71.0 g/mol
0.363 mol Cl2 ( 71.0 g/ 1 mol)= 25.8 grams
Answer:
by determining or looking up the electron configurations of the main group elements.
Explanation:
The valence electrons participate in chemical reactions. ... You can also find the core and valence electrons by determining or looking up the electron configurations of the main group elements.
Answer:
The answer to your question is: 0.3 moles of AgNO₃
Explanation:
1.0 L sample
0.1 mol of NaCl
0.1 mol of CaCl₂
AgNO₃ = ? moles
Reactions
NaCl + AgNO₃ ⇒ AgCl + NaNO₃
Then 1 NaCl mol --------------- 1 AgNO₃
0.1 mol -------------- x
x = 0.1 moles of AgNO₃ needed
CaCl₂ + 2 AgNO₃ ⇒ 2 AgCl + Ca(NO₃)₂
Then 1 mol of CaCl₂ ------------- 2 moles of AgNO₃
0.1 mol ------------- x
x = 0.2 moles of AgNO₃
Total moles of AgNO₃ = 0.1 + 0.2 = 0.3
