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kykrilka [37]
3 years ago
5

Wybierz spośród podanych określeń wlaściwości tlenku węgla4 i wpisz je w odpowiednie kolumny tabeli

Chemistry
1 answer:
andrezito [222]3 years ago
5 0
Heich emmen dedanf ńedch śhéuín i wlácgéći ńommén féirf
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"determine the mass of oxygen" in a 7.9 g sample of al2(so4)3.
jeyben [28]

Answer:

              4.43 g of Oxygen

Explanation:

As shown in Chemical Formula, one mole of Aluminium Sulfate [Al₂(SO₄)₃] contains;

                          2 Moles of Aluminium

                          3 Moles of Sulfur

                          12 Moles of Oxygen

Also, the Molar Mass of Aluminium Sulfate is 342.15 g/mol. It means,

          342.15 g ( 1 mole) of Al₂(SO₄)₃ contains  =  192 g (12 mole) of O

So,

                         7.9 g of Al₂(SO₄)₃ will contain  =  X g of O

Solving for X,

                       X  =  (7.9 g × 192 g) ÷ 342.15 g

                      X =  4.43 g of Oxygen

7 0
3 years ago
Help pls I will mark brainlest​
defon

Resources found in lithosphere: gold and iron etc

Resources found in atmosphere: Water vapor, gases etc.

4 0
3 years ago
Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of
lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

U_{2}-U_{1}=Q-W

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

dw=Pdv

The pressure is constant, so:  w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg} (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

U_{2}-U_{1}=500-(3*75)=275kJ

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

P_{1}V_{1}=nRT_{1}

P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}  

Subtracting the first from the second:

1.5P_{1}V_{1}=nR(T_{2}-T_{1})

Isolating T_{2}:

T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}

Assuming that it is water steam, n=0.1666 kmol

V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}

T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76 ºC

7 0
3 years ago
Blood is red. Is this an intensive or extensive physical property?
Anastaziya [24]

Answer: Intensive physical property

Explanation: Color is an intensive physical property since intensive properties are properties that stay the same no matter the amount of the substance is present. Blood is still red whether or not you have 2 liters of it or 4 liters.

8 0
3 years ago
What mass of carbon dioxide (co2) can be produced from 15.6 g of c6h14 and excess oxygen?
madreJ [45]
C6H14+9.5O2=6CO2 +7H20
Number of moles of C6H14=15.6/86=0.1814 moles
so moles of CO2 = 6(0.1814)=1.088 
As the c6h14 has 1 is to 6 ratio with co2 
so
0.1814=mass/44
mass of co2 produced = 47.9 g

6 0
3 years ago
Read 2 more answers
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