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pashok25 [27]
2 years ago
5

A sheet of cardboard is 1.6 m by 0.8 m. The following shapes are cut from the cardboard: ● a circular piece with radius 12 cm ●

a rectangular piece 20 cm by 15 cm ● 2 triangular pieces with base 30 cm and height 10 cm. What is the area of the remaining piece of cardboard in m²? (Consider π = 22/7)
Mathematics
1 answer:
babymother [125]2 years ago
4 0

Answer:

1.17m²

Step-by-step explanation:

Total area of cardboard=

1.6 \times 0.8 = 1.28m {}^{2}

Area of circular piece=

\pi \: r {}^{2}  = ( \frac{22}{7} )(0.12) {}^{2}  =  \frac{198}{4375} m {}^{2}

Area of rectangular piece=

0.2 \times 0.15 = 0.03m {}^{2}

Area of 2 triangular pieces=

2( \frac{1}{2} \times 0.3 \times 0.1) = 0.03m {}^{2}

Remaining area of the cardboard= Total area of cardboard - circular piece - 2 triangular pieces

1.28 -  \frac{198}{4375}  - 0.03 -0.03 =  \frac{21083}{17500}   =1.17m {}^{2}

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Step-by-step explanation:

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Consider the following 8 numbers, where one labelled
AlladinOne [14]
<h3>Answers:     x = -17  and   x = 64</h3>

====================================================

Explanation

Consider three scenarios:

  • A) The value of x is the smallest of the set (aka the min)
  • B) The value of x is the largest of the set (aka the max)
  • C) The value of x is neither the min, nor the max. So 8 < x < 39.

These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.

--------------------

We'll start with scenario A.

If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}

The range is 56, so,

range = max - min

56 = 39 - x

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--------------------

If instead we go with scenario B, then x is the max and 8 is the min

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--------------------

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