A quadratic should be in the form ax²+bx+c=0
where a b and c are all numbers
Answer: the integers are 6 and 23
Step-by-step explanation:
Let x represent one of the integers.
Let y represent the other integer.
The product of the integers is 138. This means that
xy = 138 - - - - - - - - - -1
One of the integers is seven less than five times the other integer. This means that
x = 5y - 7
Substituting x = 5y - 7 into equation 1, it becomes
y(5y - 7) = 138
5y² - 7y = 138
5y² - 7y - 138 = 0
5y² + 23y - 30y - 138 = 0
y(5y + 23) - 6(5y + 23)
y - 6 = 0 or 5y + 23 = 0
y = 6 or y = - 23/5
The only possible value of y is 6
x = 138/y = 138/6
x = 23
Answer:
e. R′
Step-by-step explanation:
Let the Sample Space be a universal set consisting of 3 red and 6 blue cards. Then the event of of getting 4 blue cards will be given
R complement = R` = Universal Set minus Red cards will give blue cards.
a. R OR O
It cannot be this option because we need 4 blue card
b. B AND O
It cannot be this choice as well because 4 is not odd.
c. R OR E
4 is even but we need blue
d. R AND O
Red and odd is again not required
e. R′ = It will give our required result.
f. E′= 4 is even if it is complemented it cannot be obtained and will be left out.
The capacity is the same as the amount because it refers to the amount of what is inside the object. Lets say you have a bag of chips it refers to the amount inside the bag of chips.
