In the figure below, g || h. Find the values of z and X.

1 answer:

7 0

107, y = 25Step-by-step explanation:z and 73 are same- side interior angles and are supplementary, sum to 180°z + 73 = 180 ( subtract 73 from both sides )z = 107z and (3y + 32) are vertical angles and are congruent, then3y + 32 = 107 ( subtract 32 from both sides )3y = 75 ( divide both sides by 3 )y = 25

You might be interested in

5.According to the Bureau of Labor Statistics, in calendar year 2000, the average duration of unemployment was 12.7 weeks, with

Ket [755]

Answer:

Probability that a randomly selected individual who was unemployed in 2000 would have been unemployed between 12 and 13 weeks is 0.83144 .

Step-by-step explanation:

We are given that according to the Bureau of Labor Statistics, in calendar year 2000, the average duration of unemployment was 12.7 weeks, with a standard deviation of 0.3 weeks.

Let X = randomly selected individual who was unemployed in 2000

Since distribution is approximately normal, so X ~ N( $\mu=12.7,\sigma^{2} = 0.3^{2}$ )

The z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 12.7 weeks

$\sigma$ = population standard deviation = 0.3 weeks

So, the probability that a randomly selected individual who was unemployed in 2000 would have been unemployed between 12 and 13 weeks is given by = P(12 < X < 13) = P(X < 13) - P(X <= 12)

P(X < 13) = P( $\frac{X-\mu}{\sigma}$ < $\frac{13-12.7}{0.3}$ ) = P(Z < 1) = 0.84134