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scoray [572]
2 years ago
10

Help pls

Mathematics
2 answers:
Nat2105 [25]2 years ago
6 0
1+1+1 times 0
and so fourth and so on if you want more detailed answers
dusya [7]2 years ago
4 0
Anything Multiplied by 0 will be 0
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I need help draw a array to represent the problem 5 x 8
xz_007 [3.2K]
Well draw a box with 10 squares going up and 20 square is going sideways and then shade and 5/8 of it
4 0
3 years ago
Which value is a solution of the equation 3 - 2x=-5?<br> 02<br> 04<br> 0-2<br> 01/5
Vikki [24]
Answer: 04
Explanation: We are given 3-2x=-5. We would subtract 3 from both sides. The equation would then look like this after subtraction from both sides: -2x=-8. We would then divide -2 by both sides so we can isolate the variable. The equation would look like this x=4.
3-2x=-5
-2x=-8
x=4
6 0
2 years ago
Read 2 more answers
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
The value of x is .... ?
alexira [117]

Answer: 96

Step-by-step explanation:

4 0
2 years ago
Find the missing length indicated?
kondor19780726 [428]

Answer:

D. 15

Step-by-step explanation:

Let the missing length be represented as x.

Thus:

(24 - x)/12 = x/20 => angle bisector theorem

Cross multiply

20(24 - x) = x(12)

480 - 20x = 12x

480 - 20x + 20x = 12x + 20x

480 = 32x

480/32 = 32x/32

15 = x

Missing length = x = 15

6 0
2 years ago
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