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3 years ago

A system of equations is graphed below. Which point represents the solution to this system?

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

8 0

$\huge \bf༆ Answer ༄$

The solution of the system of equation is the coordinates of the common point on both lines !

that is ~

$\sf( - 3,2)$

Therefore the Correct choice is C

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A coin is tossed and a spinner numbered 1 to 7 is spun. What is the probability of getting an odd number and heads

Vikki [24]

Your answer is 4/14 or 2/7. There are two possibilities when you flip a coin, heads or tails. Then for the spinner there are 7. Multiply them by each other to get the total number of outcomes of the situation of 14. Then there are only 4 odd numbers from 1-7. This means that you would only be able to get an odd number and heads 4 times.

Hope this helped!

5 0

3 years ago

Read 2 more answers

Evaluate using order of operations.

kenny6666 [7]

Answer:

26/ 43

(Decimal: 0.604651)

Step-by-step explanation:

((2)(4)−3)2+1/ 3+ 100/ 5 (2)

3 0

3 years ago

If f(x)=-x^2-1 and g(x)=x+5 then f(g(x)) =

sammy [17]

Answer:

The composition of f(g(x)) is:

$f(g(x)) = -x^2-10x-26$

Step-by-step explanation:

Given two functions are:

$f(x) = -x^2-1\\g(x) = x+5$

we have to find the composition of f and g which can also be written as: fog(x) or f(g(x))

The method to find the composition is that we will put the function g in place of x in function f

$f(g(x)) = -(x+5)^2-1\\=-(x^2+25+10x)-1\\=-x^2-25-10x-1\\=-x^2-10x-26$

Hence,

The composition of f(g(x)) is:

$f(g(x)) = -x^2-10x-26$

7 0

3 years ago

Solve this sum urgent no spam

tino4ka555 [31]

Answer:

Step-by-step explanation:

YES IS THE ANSWER BECAUSE X=9

AND 11+3=87

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3 years ago

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Find the cube roots of 27(cos 330° + i sin 330°)

Aleksandr-060686 [28]

Answer:

See below for all the cube roots

Step-by-step explanation:

DeMoivre's Theorem

Let $z=r(cos\theta+isin\theta)$ be a complex number in polar form, where $n$ is an integer and $n\geq1$ . If $z^n=r^n(cos\theta+isin\theta)^n$ , then $z^n=r^n(cos(n\theta)+isin(n\theta))$ .

Nth Root of a Complex Number

If $n$ is any positive integer, the nth roots of $z=rcis\theta$ are given by $\sqrt[n]{rcis\theta}=(rcis\theta)^{\frac{1}{n}}$ where the nth roots are found with the formulas:

$\sqrt[n]{r}\biggr[cis(\frac{\theta+360^\circ k}{n})\biggr]$ for degrees (the one applicable to this problem)
$\sqrt[n]{r}\biggr[cis(\frac{\theta+2\pi k}{n})\biggr]$ for radians

for $k=0,1,2,...\:,n-1$

Calculation

$z=27(cos330^\circ+isin330^\circ)\\\\\sqrt[3]{z} =\sqrt[3]{27(cos330^\circ+isin330^\circ)}\\\\z^{\frac{1}{3}} =(27(cos330^\circ+isin330^\circ))^{\frac{1}{3}}\\\\z^{\frac{1}{3}} =27^{\frac{1}{3}}(cos(\frac{1}{3}\cdot330^\circ)+isin(\frac{1}{3}\cdot330^\circ))\\\\z^{\frac{1}{3}} =3(cos110^\circ+isin110^\circ)$

First cube root where k=2

$\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(2)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+720^\circ}{3})\biggr]\\3\biggr[cis(\frac{1050^\circ}{3})\biggr]\\3\biggr[cis(350^\circ)\biggr]\\3\biggr[cos(350^\circ)+isin(350^\circ)\biggr]$

Second cube root where k=1

$\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(1)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+360^\circ}{3})\biggr]\\3\biggr[cis(\frac{690^\circ}{3})\biggr]\\3\biggr[cis(230^\circ)\biggr]\\3\biggr[cos(230^\circ)+isin(230^\circ)\biggr]$

Third cube root where k=0

$\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(0)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ}{3})\biggr]\\3\biggr[cis(110^\circ)\biggr]\\3\biggr[cos(110^\circ)+isin(110^\circ)\biggr]$

4 0

3 years ago