Answer:the number of advance tickets sold is 35
the number of same day tickets sold is 40
Step-by-step explanation:
Let x represent the number of advance tickets sold.
Let y represent the number of same day tickets sold.
For one performance, there were 75 tickets sold in all. This means that
x + y = 75
Advance tickets cost $20 and same-day tickets cost $25. The total amount paid for them was $1700 both tickets. This means that
20x + 25y = 1700 - - - - - - - - - - - 1
Substituting x = 75 - y into equation 1, it becomes
20(75 - y) + 25y = 1700
1500 - 20y + 25y = 1700
- 20y + 25y = 1700 - 1500
5y = 200
y = 200/5 = 40
substituting y = 40 into x = 75 - y, it becomes
x = 75 - 40
x = 35
Answer: D = x'10 − 10x'8 + 40x'6 − 80x'4 + 80x'2 − 32
Step-by-step explanation:
Step-by-step explanation:
5+2•(-3)-10/(-5)
15+2•(-3×2)
15+2•-6
15-12
3
So; the answer is 3