Since it is a square, the diagonals are exactly the same = same midpoint. hope this helps
Simple....
you have:
(-15,70) and (5,10)
Using-->>
![\frac{ y_{1} -y_{2} }{ x_{1}- x_{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%20y_%7B1%7D%20-y_%7B2%7D%20%7D%7B%20x_%7B1%7D-%20%20x_%7B2%7D%20%7D%20)
![\frac{70-10}{-15-5} = \frac{60}{-20} = -3](https://tex.z-dn.net/?f=%20%5Cfrac%7B70-10%7D%7B-15-5%7D%20%3D%20%5Cfrac%7B60%7D%7B-20%7D%20%3D%20-3%20)
Using y=mx+b...and any of the coordinates....
70= -3(-15)+b
70=45+b
70=45+b
-45 -45
25=b
y=-3x+25
Thus,your answer.
56+x=90 x=34. Hope this helps
Answer:
Your answer is 24.
Step-by-step explanation:
The data set is 22,23,23,23,24,24,25,26,26,26,28
The median of this set is 24
The mean is 24.54
The mode is 23,26
The range is 6