Answer:
15 cm on the map is equal to 25 miles.
Step-by-step explanation:
Given that,
On a map, 9 cm represents 15 miles.
The distance between two cities is 15 cm. We need to find the distance in miles.
9 cm = 15 miles

So, 15 cm is equal to,

So, 15 cm on the map is equal to 25 miles.
F(x)=
![\sqrt[3]{x+2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%2B2%7D%20)
to solve for the inverse of a function you do 4 steps:
1. subsitute f(x) with y
2. switch y and x places
3. solve for y
4. subsitute y with f⁻¹(x)
so we have
f(x)=
![\sqrt[3]{x+2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%2B2%7D%20)
subsitute f(x) with y
y=
![\sqrt[3]{x+2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%2B2%7D%20)
switch x and y
x=
![\sqrt[3]{y+2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7By%2B2%7D%20)
solve for y
x=
![\sqrt[3]{y+2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7By%2B2%7D%20)
cube both sides

=y+2
subtract 2 from both sides

=y
subsitute y with f⁻¹(x)
f⁻¹(x)=

the answer is f⁻¹(x)=
the correct answer for plato users is
2!!
Answer:

Step-by-step explanation:
we know that
In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference
we have

Let



The common difference is 
We can write an Arithmetic Sequence as a rule

where
a_n is the nth term
d is the common difference
a_1 is the first term
n is the number of terms
Find the 63rd term of the arithmetic sequence
we have

substitute




Answer:
see explanation
Step-by-step explanation:
Given
+ 2c + 11
=
-
+ 2c + 11
= 3c - 1 + 2c + 11
= 5c + 10
(b)
We have the expression
5c + 10 ← factor out 5 from each term
= 5(c + 2)