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sukhopar [10]
3 years ago
6

In a certain Algebra 2 class of 27 students, 11 of them play basketball and 9 of them play baseball. There are 11 students who p

lay neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Mathematics
1 answer:
grigory [225]3 years ago
8 0
<h2>Answer:</h2><h2>The probability of students who play both basketball and baseball =  \frac{4}{27}</h2>

Step-by-step explanation:

In a certain Algebra class,

The total number of students = 27 students

Let the students playing basketball be represented as A and baseball as B.

The students who play basketball, A= 11

The students who play basetball,B =9

The students who play neither sport,  = 11

The students who play both basketball and baseball,  = ?

By formula, P(AUB)=P(A)+P(B)-P(A∩B)

Substituting the values in the equation, we get

P(AUB) = \frac{11}{27} + \frac{9}{27} - \frac{16}{27}

 P(AUB) = \frac{4}{27}

The probability of students who play both basketball and baseball =  \frac{4}{27}

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