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3 years ago

Pls help me im stuck and i need to pass this lesson

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

5 0

The answer is 5

The height of the right side is 15in the other side parallel is 10in leaving the top to be 5in

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If 4321 - 4322 = 10 <br> Then what's 3321 - 3322 = ?

ArbitrLikvidat [17]

Answer:

10 sorry if i'm wrong

Step-by-step explanation:

8 0

3 years ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

4 years ago

What decimal is equivalent to 122/11?<br />do u divide 11 into 122 ?

Sav [38]

122/11....u divide 122 by 11...or how many times does 11 go into 122.
122/11 = 11.09 with a line over the 09 because it is repeating

8 0

3 years ago

Can somebody help me find the slope of this problem ??

andreev551 [17]

Answer:

The slope is 3/4

Please correct me if I am wrong please and thank you

Step-by-step explanation:

I use the slope formula $\frac{y2-y1}{x2-x1}$

Plug in (2,1) and (-2,-2)

1-(-2)/2-2

= 3/4

7 0

3 years ago

Read 2 more answers

If one battery is 5 cm long how many batteriess would i need to get to 3 meters (need work )

dem82 [27]

1. So in one meter,there are 100 centimeters.
2. Multiply 100 by 3 which equals 300.
3. Divide 300 by 5 which equals 60.
4. 60 is your answer!!!

Hope this helped!! :)

4 0

3 years ago