Solving Surface Area Problems hi, please help me with this question i really need some help

Mathematics

1 answer:

fredd [130]2 years ago

5 0

The surface area of the rectangular prism is of 144 m².

<h3>What is a rectangular prism?</h3>

A rectangular prism is a solid that has three dimensions:

Length l.

Width w.

Height h.

It's surface area is given by:

$S = 2(lw + lh + wh)$

In this problem, the dimensions are: $l = w = 6, h = 3$ .

Hence:

$S = 2[6(6) + 6(3) + 6(3)] = 144$

The surface area of the rectangular prism is of 144 m².

You can learn more about surface area of a rectangular prism at brainly.com/question/17223528

You might be interested in

I REALLY NEED HELP!!!!

Anna35 [415]

Divide x^4+x^3+7x^2-6x+8 by x+2+2x+8 using long polynomial division.

Answer:
x^2-x+1

8 0

2 years ago

Read 2 more answers

100 POINTS PLUS BRAINLIEST!!!! QUESTION ATTACHED

Oduvanchick [21]

Answer:

Step-by-step explanation:

You have to have exactly the same thing underneath the radical. So for example in choice A you have sqrt(2) and sqrt(3) underneath the radical. They are not the same. Choice A is not the answer.

Choice B has the same problem sqrt(5) is not the same thing as sqrt(3) and choice B is not the answer.

Choice C has sqrt(5) and sqrt(6) as your choice. They are not the same. C is not correct.

D is the answer. Both choices have sqrt(7) as the radicals. They are both 7. They are the same.

6 0

3 years ago

Read 2 more answers

Please help me with this question.

Evgen [1.6K]

Answer:

$\purple{ \boxed{\frac{d^{2} y}{dx ^{2} } = \frac{132}{ {x}^{13} } }}$

Step-by-step explanation:

$y = \frac{1}{ {x}^{11} } \\ y = {x}^{ - 11} \\ \frac{dy}{dx} = \frac{d}{dx} {x}^{ - 11} \\ \frac{dy}{dx} = - 11{x}^{ - 11 - 1} \\ \frac{dy}{dx} = - 11{x}^{ - 12} \\ \\ \frac{d}{dx} \bigg(\frac{dy}{dx} \bigg) = \frac{d}{dx} ( - 11 {x}^{ - 12} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = - 11\frac{d}{dx} ( {x}^{ - 12} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = - 11( - 12{x}^{ - 13} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = 132{x}^{ - 13} \\ \\ \huge \red{ \boxed{\frac{d^{2} y}{dx ^{2} } = \frac{132}{ {x}^{13} } }}$