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OlgaM077 [116]
3 years ago
14

2² + 2[2(3+1)(3-2)-1]

Mathematics
1 answer:
laila [671]3 years ago
4 0

Answer:

18

Step-by-step explanation:

hope this helps! :D

have a miraculous day!! <3

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What is the measure of angle M? Type only the number:
Aleks04 [339]

Answer: 30

Step-by-step explanation:

all angle degrees added up = 180 degrees as I said before.

180 = 102+48+M

180 = 150+M

M = 30

4 0
3 years ago
PLZ HELP ASAP!! 100 points!!! <br><br> Are these examples of direct variation? Please explain
Grace [21]

Answer:

mathematical relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other. 

8 - direct variation Since the equation can be written in the form y=kx. , y varies directly with x and k. The constant of variation, k, is 3.25

9 - When solving for y, y=5x-9 so y doesn't vary directly with x.

y doesn't vary directly with x

10 - direct variation Since the equation can be written in the form y=kx, y varies directly with x and k. The constant of variation, k, is -2.4

5 0
3 years ago
Read 2 more answers
If the mountain is 1,200 feet tall, find the length of the ski lift
Nina [5.8K]
The length of the sky lift is 3.387.05 ft
Step-by-step explanation;
By an online search, i found that the sky lift
rises at an angle of 20.75 degrees.
Then we can think on a triangle rectangle, such
that:
One cathetus is 1200ft, this is the opposite
cathetus to the angle of 20.75°
The length of the ski lift would be the
hypotenuse of this triangle rectangle.
Then we can use the relationship:
Sin(a) = opposite cathetus/hypoteuse.
such that:
a = 20.75°
opposite cathetus=1200ft
then:
sin(20.75°) = 1200ft/hypotenuse
hypotenuse =1200ft/sin(20.759) =3.387.05 ft
The length of the sky lift is 3.387.05 ft
7 0
3 years ago
Please Help Quickly!!!<br><br> Find the limit if f(x) = x^3
jeka94

Answer:

Option b. 12

Step-by-step explanation:

This exercise asks us to find the derivative of a function using the definition of a derivative.

Our function is f(x) = x^{3}. Therefore:

f(2+h) = (2+h)^{3}

f(2) = (2)^{3} = 8

Then:

\lim_{h \to \0} \frac{f(2+h)-f(2)}{h}=\lim_{h \to \0} \frac{(2+h)^{3}-8}{h}

Expanding:

\lim_{h \to \0} \frac{(2+h)^{3}-8}{h} =\lim_{h \to \0} \frac{8+ h^{3} +6h(2+h) -8}{h} =\lim_{h \to \0} \frac{h^{3} +6h(2+h)}{h}

\lim_{h \to \0} \frac{h^{3}+ 6h(2+h)}{h} =\lim_{h \to \0} h^{2} + 6(2+h)

Now, if x=0:

\lim_{h \to \0} \frac{f(2+h)-f(2)}{h} = (0)^{2} +6(2+0) = 12

4 0
3 years ago
2.15 divided by 38 =?
zmey [24]

Answer:

0.06, but this is rounded

Step-by-step explanation:

2.15/38=0.06 (rounded)

Hope this helps and have a great day (づ ̄ v ̄)づ

4 0
3 years ago
Read 2 more answers
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