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postnew [5]
2 years ago
7

Write two expressions for the perimeter of a square. Explain what information is in

Mathematics
1 answer:
Gnoma [55]2 years ago
3 0
Two expressions for the perimeter of a square are:
4a
- a represents one side of the square
a + a + a + a
- a representa one side of the square

the first expression does not include any addition. But the two expressions are actually equivalent.
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A city has a populations of 38,802,500 people. estimate the population ot hte nearest ten million
Zolol [24]

Answer:

39,000,000

Roundend to the nearest 1,000,000 or

the Millions Place.

38,802,500.0000000

Roundend to the nearest 0.0000001 or

the Ten Millionths Place.

8 0
2 years ago
In the data set below, what is the range? 9, 4, 9, 2, 8, 2, 1
noname [10]
First put these in order from least to greatest.

1,2,2,4,8,9,9 is the correct order
Range is when we subtract the greatest value of our data set from the smallest so in our case it would be 9-1 which leaves us with our answer that 8 is your range.
7 0
3 years ago
What is the answer to this question ?
Arisa [49]

Answer:

4

Step-by-step explanation:

h(7)= 7²-1= 49-1= 48

f(h(7))= 48/3 -12

= 16-12

= 4

7 0
3 years ago
How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
4 0
3 years ago
If x-12√x + 36 = 0 what is the value of x A. 6 B. 6^2 C. 6^3 D. 6^4
Snowcat [4.5K]
Let
\sqrt{x}  = a
then you will have a^2-12a+36=0 and then you can just factor to find a
8 0
3 years ago
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