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adoni [48]
3 years ago
11

Find the least number must be added to 4015 to make it a perfect square. also,find the square root of the perfect square so obta

ined.
Mathematics
1 answer:
Vladimir [108]3 years ago
7 0

To solve this, I used guess and check.

I started by finding 60²=3600 and 70²=4900. 70² is too much, so I then did 65²=4,225.

After 65², I did 62²=3,844. I knew that was pretty close, so I did 64. 64²=4,096 and 63²=3,969. So, 64² was it.

4,096-4015=81

So, you would need to add 81 to 4015 in order to receive a perfect square, which is 64²(4,096).

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Where is the other one?
4 0
3 years ago
One leg of a right triangle has a length of 7 m. The other side have lengths that are consecutive integers. Find these lengths
Darina [25.2K]

Answer:

6 and 5

Step-by-step explanation:

Consecutive means that it is continuous, and since the triangle largest side (7) has to be less than the additive of two other sides. Therefore 6 and 5. Hope this helps.

4 0
3 years ago
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Find P on AB that is 2/3 of the distance from A(-3,-5) to B(9,4).
Ludmilka [50]

A line segment can be divided into ratios.

<em>The coordinate of P on line segment AB is (5,1)</em>

Given

A = (-3,-5)

B = (9,4)

The position of P from A to B is:

P_A = \frac 23

So, from P to B would be:

P_B =1 -  \frac 23

P_B = \frac 13

So, the ratio is:

m : n = \frac 23 : \frac 13

Simplify

m : n = 2 :1

<u>The coordinate of point P is:</u>

P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})

So, we have:

P = (\frac{2 \times 9 + 1 \times -3}{2 + 1},\frac{2 \times 4 + 1 \times -5}{2 + 1})

P = (\frac{15}{3},\frac{3}{3})

P = (5,1)

<em>Hence, the coordinate of P is (5,1)</em>

Read more about line ratios at:

brainly.com/question/8847082

8 0
3 years ago
-3(5x-10)=[?]x + [ ]
Setler [38]

Answer:

-15x + 30

Step-by-step explanation:

-3(5x -10)

-15x + 30

7 0
2 years ago
What is the answer to this? Will someone help me?<br> 5+(9)(6)
sineoko [7]
Answer: 59
explanation: PEMDAS, first multiply 9x6 as they are multiplication then add

good luck!
4 0
3 years ago
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