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2 years ago

What are the dimensions of the poster at one-half its current size?

Mathematics

1 answer:

zhuklara [117]2 years ago

8 0

Answer:

2 cm by 5 cm

Step-by-step explanation:

2 cm by 5 cm are the dimensions of the poster at one-half its current size

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Simplify -2 1/9 -(-4 1/3)

vesna_86 [32]

Answer:

$\frac{20}{9}$ or $2 \frac{2}{9}$

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2 years ago

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What’s the solution to this equation 2+x=7/8x-15

Nostrana [21]

Answer:x=−136

Step-by-step explanation: Step 1: Simplify both sides of the equation.

2+x=

x−15

2+x=

x+−15

x+2=

x−15

Step 2: Subtract 7/8x from both sides.

x+2−

x−15−

x+2=−15

Step 3: Subtract 2 from both sides.

x+2−2=−15−2

x=−17

Step 4: Multiply both sides by 8.

8*(

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2 years ago

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I can't solve number 12. If you solve the others, much appreciated.

saul85 [17]

Answer is 18 due to the theory cause

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2 years ago

If you were born in 1925 how old are you in 1967

motikmotik

If you were born in 1925 you would be 42 years old in 1967

1967 - 1925 = 42

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3 years ago

Find the kissing lengths of the sides of the triangle.

alina1380 [7]

Answer: The last option.

Step-by-step explanation:

The triangle shown in the figure attached is a right triangle.

1. You can calculate the lenght a as following:

$sin\alpha=\frac{opposite}{hypotenuse}$

$opposite=a\\hypotenuse=6in\\\alpha=30\°$

Substitute values and solve for a. Then, you obtain:

$sin(30\°)=\frac{a}{6in}\\a=6in*sin(30\°)\\a=3in$

2. You can calculate the lenght b as following:

$cos\alpha=\frac{adjacent}{hypotenuse}$

$adjacent=b\\hypotenuse=6in\\\alpha=30\°$

Substitute values and solve for b. Then, you obtain:

$cos(30\°)=\frac{b}{6in}\\b=6in*cos(30\°)$

$b=3\sqrt{3}in$

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3 years ago