Answer:
A. 
.
Step-by-step explanation:
We have been given an inequality 
. We are asked to solve the given inequality for x.
Using distributive property, we will get:
Subtract 2 from both sides:
Divide both sides by 7:
Therefore, option A is the correct choice.
Answer:
2
Step-by-step explanation:
Degree is the highest power of a term
I hope im right!
Answer:
Let the polynomial be f(x) = 5x – 4x^2 + 3
Now, for x = 2,
f(2) = 5(2) – 4(2)^2 + 3
=> f(2) = 10 – 16 + 3 = –3
Or, the value of the polynomial 5x – 4x^2 + 3 at x = 2 is -3.
Similarly, for x = –1,
f(–1) = 5(–1) – 4(–1^)2 + 3
=> f(–1) = –5 –4 + 3 = -6
The value of the polynomial 5x – 4x2 + 3 at x = -1 is -6.
Answered by GAUTHMATH
hey is this all too then question
Answer:
Demand is Elastic when Price > 200 ; Demand is inelastic when Price < 200
Step-by-step explanation:
p = 400 - 4x
4x = 400 - p
x = (400 - p) / 4 → x = 100 - p/4
Elasticity of demand [ P ed ] = (Δx / Δp) x (p / x)
Δx / Δp [Differentiating x w.r.t p] = 0 - 1/4 → = -1/4
P ed = <u>-1</u> x<u> p </u>
4 (400 - p)/4
= <u>-1</u> x <u> 4p </u> = -p / (400-p)
4 (400 - p)
Price Elasticity of demand : only magnitude is considered, negative sign is ignored (due to negative price demand relationship as per law of demand).
So, Ped = p / (400 - p)
Demand is Elastic when P.ed > 1
p / (400-p) > 1
p > 400 - p
p + p > 400 → 2p > 400
p > 400 / 2 → p > 200
Demand is inelastic when P.ed < 1
p / (400-p) < 1
p < 400 - p
p + p < 400 → 2p < 400
p < 400 / 2 → p < 200
