Answer:
Mean rate of reaction produced = 0.533 g/sec (approx.)
Explanation:
Given:
Reaction produced = 1.6 gram
Time taken = 30 sec
Find:
Mean rate of reaction produced
Computation:
Mean rate of reaction produced = Reaction produced / Time taken
Mean rate of reaction produced = 1.6 / 30
Mean rate of reaction produced = 0.533 g/sec (approx.)
Yes it can cause you put epsom salt in a bath and theirs magnesium in that and it’s good for your body and takes fat from your body
Answer:
The mass percentage of carbon can be found easily using the molar mass of C6H12O6, 180.1559 g/mol. We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass. C6H12O6 = CO2 + C3H6O3 + CH3OCH3 Take fructose for example. Compound.
Explanation: I looked it up
Answer:
When [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate
Explanation:
Ksp of BaF₂ is:
BaF₂(s) ⇄ Ba²⁺(aq) + 2F⁻(aq)
Ksp = 1.7x10⁻⁶ = [Ba²⁺] [F⁻]²
The solution will produce BaF₂(s) -precipitate- just when [Ba²⁺] [F⁻]² > 1.7x10⁻⁶.
As the concentration of [Ba²⁺] is 0.0144M, the product [Ba²⁺] [F⁻]² will be equal to ksp just when:
1.7x10⁻⁶ = [Ba²⁺] [F⁻]²
1.7x10⁻⁶ = [0.0144M] [F⁻]²
1.18x10⁻⁴ = [F⁻]²
0.0109M = [F⁻]
That means, when [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate
Answer:
0.05 M
Explanation:
Mass of benzoic acid= 0.158g
Volume of benzoic acid= 100 mL
Volume of sodium hydroxide = 27.84mL
Molar mass of benzoic acid= 122g/mol
Number of moles of benzoic acid= 0.158g/122g/mol= 1.3 × 10^-3 moles
C= no of moles/volume
C= 1.3 × 10^-3 moles × 1000/100
C= 0.013M
So;
Volume of acid VA = 100mL
Concentration of acid CA= 0.013M
Volume of Base VB = 27.84mL
Concentration of Base CB= ???
Number of moles of acid NA =1
Number of moles of Base NB= 1
From;
CAVA/CBVB= NA/NB
CAVANB= CBVBNA
CB= CAVANB/VBNA
CB= 0.013 × 100 × 1/27.84 × 1
CB= 0.05 M
