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krok68 [10]
3 years ago
7

Write an equation in slope-intercept form of the line that is perpendicular to the line represented by 8x-4y+9=0 and passes thro

ugh the point at (2, 3).
Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

Step-by-step explanation:

y - 3 = (-1/2)(x - 2)

Solve 8x-4y+9=0 for y so as to find the slope of this given line:

8x + 9 = 4y, or y = 2x + 9/4.  The slope of the given line is 2.  The slope of any line perpendicular to this one is the negative reciprocal of 2, which is -1/2.

Use the point-slope formula:  y - k = m(x - h ).  (h, k) is (2, 3) and m is -1/2.

Then we have:  y - 3 = (-1/2)(x - 2)

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