Ask question

Ask question

All categories

3 years ago

7

Write an equation in slope-intercept form of the line that is perpendicular to the line represented by 8x-4y+9=0 and passes thro

ugh the point at (2, 3).

1 answer:

WARRIOR [948]3 years ago

4 0

Answer:

Step-by-step explanation:

y - 3 = (-1/2)(x - 2)

Solve 8x-4y+9=0 for y so as to find the slope of this given line:

8x + 9 = 4y, or y = 2x + 9/4. The slope of the given line is 2. The slope of any line perpendicular to this one is the negative reciprocal of 2, which is -1/2.

Use the point-slope formula: y - k = m(x - h ). (h, k) is (2, 3) and m is -1/2.

Then we have: y - 3 = (-1/2)(x - 2)

You might be interested in

What's the area of this shape

spin [16.1K]

Answer:

L x W x H

Step-by-step explanation:

if my calculations are correct the length is 2 the width is 3 and the height is 3

Therefore the answer is (2 x 3) = 6 x3

So the answer is 18.

Hope it helps, if it is incorrect than i am extremely sorry, wish you the best of luck and have a great day/midday/evening. BYYEEEEEEE

5 0

2 years ago

Graph y = -1/3x+5<br><br> will give brainiest

Mnenie [13.5K]

Answer:

THATS THE ANSWER

Step-by-step explanation:

3 0

3 years ago

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago

I need a little help :)

Naily [24]

So firstly, square root 9a^2 and 49: $3a+7\sqrt{b}-a+\sqrt{b}$

Next, combine like terms, and your answer will be $2a+8\sqrt{b}$ , or the third option.

3 0

3 years ago

Please help me I will mark brain-list

kozerog [31]

Answer:

q12 is 8

q13 is 81

Step-by-step explanation:

100*6 =600 / 75 = 8

90*72 = 6480 / 80 = 81

6 0

3 years ago

Read 2 more answers