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SVETLANKA909090 [29]
2 years ago
15

How can I solve this?

Mathematics
2 answers:
LekaFEV [45]2 years ago
7 0
Try and divide the hour by the law
elixir [45]2 years ago
3 0

Answer:

x=8/21

Step-by-step explanation:

(3/4)/(2/7) = 1/x

(3/4)x = (2/7)

x = (2/7) / (3/4)

x = (2/7) * (4/3)

x = 8/21

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Evaluate for x = 3 and y = 4: x^-2y^2/x^0y^3 1/36 4/9 1024/9
GrogVix [38]

Answer:

\frac{1}{36}

Step-by-step explanation:

Evaluating the numerator and denominator before evaluating

Using the rule of exponents

a^{-n} ⇔ \frac{1}{a^{n} }, a^{0} = 1

Thus

x^{-2}y² ← substitute values into expression

= 3^{-2} × 4² = \frac{1}{9} × 16 = \frac{16}{9}

and denominator

x^{0}y^{3} = 1 × 4³ = 1 × 64 = 64

Now dividing

\frac{16}{9} ÷ 64

= \frac{16}{9} × \frac{1}{64} ( cancel 16 and 64 )

= \frac{1}{9(4)} = \frac{1}{36}

4 0
2 years ago
Need help will give thanks and brainliest
Lina20 [59]

Answer : y = 11x + 24

7 0
2 years ago
Read 2 more answers
The sum of two number is 27. One number is 3more than the other number. Write and solve a system of equations to find the two nu
Sladkaya [172]

Answer:

One number is 15 and 3 less than that is 12 so that is your other number

3 0
3 years ago
How to solve it? What is the result of this question
lesantik [10]
Remember the order of operations. 
Dividing fractions means multiplying a reciprocal. 
3÷1/3=3×3/1=9
9-9+1=1
1 is your answer. 
:)
3 0
2 years ago
Read 2 more answers
Please show all steps... finals coming up!
Rama09 [41]
1) find x
 y=1/(x+3) -4
 y+4=1/(x+3) -4+4
 y+4=1/(x+3) 

x+3 =1/(y+4)
x= 1/(y+4)  - 3

2) change x on y , and y on x

x= 1/(y+4)  - 3
y= 1/(x+4)  - 3   This is an answer.
4 0
2 years ago
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