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Stella [2.4K]
2 years ago
10

How does the mass effect the gravitational force between objects?.

Physics
1 answer:
Anna11 [10]2 years ago
6 0

Answer: Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

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A sample of gas has a volume of 25L at a pressure of 200 kPa and a temperature of 25°C. What would be the volume if the pressure
frozen [14]

Answer:

18 L

Explanation:

Use ideal gas law:

PV = nRT

Find initial number of moles, but first convert to units that match the gas constant units.

(200,000 Pa) (0.025 m³) = n (8.314 Pa m³ / mol / K) (25 + 273.15 K)

n = 2.017 mol

At the new pressure and temperature:

(250,000 Pa) V = (2.017 mol) (8.314 Pa m³ / mol / K) (0 + 273.15 K)

V = 0.018 m³

V = 18 L

3 0
4 years ago
A student takes the elevator up to the fourth floor to see her favorite physics instructor. She stands on the floor of the eleva
never [62]

Answer:

N = 1364 N

Explanation:

given data

accelerate upward = 5.70 m/s²

mass = 88.0 kg

solution

normal force is in upward direction so, weight of the student in downward direction and acceleration is in upward direction so formula is express as

N - mg = ma        ...........................1

N = m × (g+a)

put here value

N = 88.0 × (9.8 + 5.70)

N = 1364 N

8 0
3 years ago
If a sinusoidal electromagnetic wave with intensity 18 W/m2 has an electric field of amplitude E, then a 36 W/m2 wave of the sam
Neporo4naja [7]

Answer:

The  correct option is D

Explanation:

From the question we are told that

  The intensity of the first  electromagnetic wave is  I =  18 \  W/m^2

  The amplitude of the electric field is  E_{max}_1 =A

   The intensity of the second electromagnetic wave is  I =  36 \  W/m^2

Generally the an electromagnetic wave intensity is mathematically represented as

       I  =  \frac{1}{2} *  \epsilon_o  * c  * E_{max}^2

Looking at this equation we see that

     I \ \ \alpha  \ \ E^2_{max}

=>  \frac{I_1}{I_2}  =  [ \frac{ E_{max}_1}{ E_{max}_2} ] ^2

=>   E_{max}_2 = \sqrt{\frac{x}{y} }  *  E_{max}_1

=>  E_{max}_2 = \sqrt{\frac{36}{18} }  * E        

=>  E_{max}_2 = \sqrt{2 }  E        

5 0
3 years ago
A railroad car of 2000 kg coasting at 3.0 m/s overtakes and locks with an identical car coasting on the same track in the same d
serg [7]
The key is in "they lock together". This tells you this is a complete inelastic collision and therefore you can use the formula:
m1*v1+m2*v2=v(m1+m2)
Plug in numbers:
2000*3+2000*2=v(2000+2000)
so v=2 m/s, obviously in the same direction of motion in which they were both moving.
4 0
4 years ago
What is the magnitude of the electric field in a region where the potential is given by the expression V = ax2 + b where a = −50
sweet [91]

Answer:

E = 1000 x

Explanation:

The electric potential and the electric field are related by the formula

        dV = - E . dx

Bold represents vectors.

The point represents the scalar product, in this case we calculate the electric field in the x-axis and the potential is also in this axis so the scalar product is reduced to the algebraic product

        E = dV /dx

Let's make the derivative

        E = - 2ax

Let's replace the values

        E = -2 (-500) x

        E = 1000 x

5 0
3 years ago
Read 2 more answers
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