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Aleonysh [2.5K]
3 years ago
8

Label these as balanced or unbalanced:

Physics
2 answers:
kvasek [131]3 years ago
4 0

Answer:

  1. A book lying on a table  - Balanced force
  2. An airplane cruising in level flight  - Balanced
  3. A rock falling from a cliff  - Unbalanced force
  4. A bridge collapsing in an earthquake  -  Unbalanced force
  5. A man sitting on a park bench  - Balanced force
  6. A space shuttle taking off  - Unbalanced force
  7. A car maintaining a constant speed on a straight road  - Balanced force
  8. An airplane landing - Unbalanced force

Explanation:

Usually, one or more forces act on a body at an instant of time. When these forces acting on a body and bring the body in the equilibrium position, the force is said to be balanced. The unbalanced force changes the equilibrium state of the body.

As in the case of an airplane cruising in a level flight, the weight of the plane will be equal to the lift force and the thrust is equal to the drag. So the plane is experiencing a balanced force.

erik [133]3 years ago
3 0

Answer:

1. A book lying on a table  (Balanced force)  

2.An airplane cruising in level flight (Balanced force)

3.A rock falling from a cliff (Unbalanced force)

4.A bridge collapsing in an earthquake (Unbalanced force)

5.A man sitting on a park bench (Balanced force)  

6.A space shuttle taking off (Unbalanced force)

7.A car maintaining a constant speed on a straight road (Balanced force)

8.An airplane landing (Unbalanced force)

Explanation:

An object will be in equilibrium or balanced state if the sum off all the forces and toques on that object will be equal to zero.  

in case of book lying on the table its weight is balanced by the normal force exerted by the table. So, balance force is acting on it. Same analogy can be applied to a man sitting on bench.  

When air plane cruise in level flight, the weight of airplane is equal to the lift force and drag force is equal to the thrust force. Hence, balanced force acts on the airplane.

When car runs with the uniform speed on the road, engine force is equal to the frictional force. Hence, balanced force acts on the car.  

In all other cases unbalance forces act which can be judged just by looking statements.  

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Sergio [31]

Answer:

a) y = 2.4 x 10⁻³ m = 0.24 cm

b) y = 3.2 x 10⁻³ m = 0.32 cm

Explanation:

The formula of Young's Double Slit experiment will be used here:

y = \frac{\lambda L}{d}\\\\

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y = distance between dark spots = ?

λ = wavelength

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d = slit width = 4 x 10⁻⁴ m

a) FOR λ = 480 nm = 4.8 x 10⁻⁷ m:

y = \frac{(4.8\ x\ 10^{-7}\ m)(2\ m)}{4\ x\ 10^{-4}\ m}

<u>y = 2.4 x 10⁻³ m = 0.24 cm</u>

<u></u>

a) FOR λ = 640 nm = 6.4 x 10⁻⁷ m:

y = \frac{(6.4\ x\ 10^{-7}\ m)(2\ m)}{4\ x\ 10^{-4}\ m}

<u>y = 3.2 x 10⁻³ m = 0.32 cm</u>

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2 years ago
Which countries have high productivity, but are not among the top 10 for human development? Check all that apply.
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Belgium

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These are the ones that are in the High Productivity chart, but not in the HDI chart

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. If measurements of a gas are 75L and 300 kilopascals and then the gas is measured a second time and found to be 50L, describe
julia-pushkina [17]
By Boyle's law:

P₁V₁ = P₂V₂

300*75 = P<span>₂*50

</span>P<span>₂*50= 300*75
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3 0
3 years ago
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A circular loop with radius r is rotating with constant angular velocity ω in a uniform electric field with magnitude E. The axi
inn [45]

Answer:

\Phi_{E} = E\pi r^2 \omega t

Explanation:

The electric flux is defined as the multiple of electric field and the area that the electric field passes through, such that

\Phi_{E} = \vec{E}\vec{A}

When calculating the electric flux, the angle between the directions of electric field and the area becomes important, especially if the angle is changing with time.

The above formula can be rewritten as follows

\Phi_{E} = EA\cos(\theta)

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If the loop is rotating with constant angular velocity ω, then the angle can be written as follows

\theta = \omega t

At t = 0, cos(0) = 1 and the electric flux through the loop is at its maximum value.

Therefore the electric flux can be written as a function of time

\Phi_{E} = E\pi r^2 \omega t

3 0
3 years ago
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