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3 years ago

Label these as balanced or unbalanced:

Physics

2 answers:

kvasek [131]3 years ago

4 0

Answer:

A book lying on a table - Balanced force
An airplane cruising in level flight - Balanced
A rock falling from a cliff - Unbalanced force
A bridge collapsing in an earthquake - Unbalanced force
A man sitting on a park bench - Balanced force
A space shuttle taking off - Unbalanced force
A car maintaining a constant speed on a straight road - Balanced force
An airplane landing - Unbalanced force

Explanation:

Usually, one or more forces act on a body at an instant of time. When these forces acting on a body and bring the body in the equilibrium position, the force is said to be balanced. The unbalanced force changes the equilibrium state of the body.

As in the case of an airplane cruising in a level flight, the weight of the plane will be equal to the lift force and the thrust is equal to the drag. So the plane is experiencing a balanced force.

erik [133]3 years ago

3 0

Answer:

1. A book lying on a table (Balanced force)

2.An airplane cruising in level flight (Balanced force)

3.A rock falling from a cliff (Unbalanced force)

4.A bridge collapsing in an earthquake (Unbalanced force)

5.A man sitting on a park bench (Balanced force)

6.A space shuttle taking off (Unbalanced force)

7.A car maintaining a constant speed on a straight road (Balanced force)

8.An airplane landing (Unbalanced force)

Explanation:

An object will be in equilibrium or balanced state if the sum off all the forces and toques on that object will be equal to zero.

in case of book lying on the table its weight is balanced by the normal force exerted by the table. So, balance force is acting on it. Same analogy can be applied to a man sitting on bench.

When air plane cruise in level flight, the weight of airplane is equal to the lift force and drag force is equal to the thrust force. Hence, balanced force acts on the airplane.

When car runs with the uniform speed on the road, engine force is equal to the frictional force. Hence, balanced force acts on the car.

In all other cases unbalance forces act which can be judged just by looking statements.

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Nady [450]

The first collision because a greater amount of momentum must be taken and used in order to push the cart back, giving it a greater mass and impulse

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4 years ago

If you stood on a planet with four times the mass of Earth, and twice Earth's radius, how much would you weigh?

nikdorinn [45]

Answer:

1/4 times your earth's weight

Explanation:

assuming the Mass of earth = M

Radius of earth = R

∴ the mass of the planet= 4M

the radius of the planet = 4R

gravitational force of earth is given as = $\frac{GM}{R^{2} }$

where G is the gravitational constant

Gravitational force of the planet = $\frac{G4M}{(4R)^{2} }$

= $\frac{G4M}{16R^{2} }$

= $\frac{GM}{4R^{2} }$

recall, gravitational force of earth is given as = $\frac{GM}{R^{2} }$

∴Gravitational force of planet = 1/4 times the gravitational force of the earth

you would weigh 1/4 times your earth's weight

3 0

4 years ago

A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much en

dem82 [27]

Answer:

E = 0.18 J

Explanation:

given,

Potential of the battery,V = 9 V

Charge on the circuit, Q = 20 m C

= 20 x 10⁻³ C

energy delivered in the circuit

E = Q V

E = 20 x 10⁻³ x 9

E = 180 x 10⁻³

E = 0.18 J

Energy delivered in the circuit is equal to E = 0.18 J

7 0

4 years ago

Water flows through a cast steel pipe (k = 50 W m.K, ε = 0.8) with an outer diameter of 104mm and 2 mm wall thickness. Calculate

masha68 [24]

Answer:

The heat loss per unit length is $\frac{Q}{L} = 2981 W/m$

Explanation:

From the question we are told that

The outer diameter of the pipe is $d = 104mm = \frac{104}{1000} = 0.104 m$

The thickness is $D = 2mm = \frac{2}{1000} = 0.002m$

The temperature of water is $T = 90^oC = 90 + 273 = 363K$

The outside air temperature is $T_a = -10^oC = -10 +273 = 263K$

The water side heat transfer coefficient is $z_1 = 300 W/ m^2 \cdot K$

The heat transfer coefficient is $z_2 = 20 W/m^2 \cdot K$

The heat lost per unit length is mathematically represented as

$\frac{Q}{L} = \frac{2 \pi (T - Ta)}{ \frac{ln [\frac{d}{D} ]}{z_1} + \frac{ln [\frac{d}{D} ]}{z_2}}$

Substituting values

$\frac{Q}{L} = \frac{2 * 3.142 (363 - 263)}{ \frac{ln [\frac{0.104}{0.002} ]}{300} + \frac{ln [\frac{0.104}{0.002} ]}{20}}$

$\frac{Q}{L} = \frac{628}{0.2107}$

$\frac{Q}{L} = 2981 W/m$

6 0

3 years ago

Which question cannot be answered through making measurements?

Bond [772]

A. is the answer for this question

5 0

4 years ago