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3 years ago

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benzene c6h6 and toluene c6h5ch3 for ideal solutions. at 35c the vapor pressure of benzene is 160 torr and that of toluene is 50

torr in an experiment 3.8 mol of benzene and 5.7 of toluene are placed in a closed container at 35 c and allowed to come to equilibrium. what is the mole fraction of tp;uene in the capor phase

1 answer:

LuckyWell [14K]3 years ago

6 0

Answer:

mole fraction of toluene 0.53

Explanation:

given data:

vapor pressure of benzene = 160 torr

vapor pressure of toluene = 50 torr

mole of benzene = 3.8 mol

mole of toluene = 5.7 mol

calculate total pressure

here total pressure = mole fraction of toluene x vapour pressure of toluene + mole fraction of benzene x vapor pressure of benzene

mole fraction of toluene $= \frac{5.7}{5.7+3.8}$

mole fraction of Benzene $= \frac{3.8}{5.7+3.8}$

$= \frac{5.7}{( 5.7 + 3.8 )}*50 + \frac{3.8}{5.7 + 3.8}*160$

= 94 torr

we have mole fraction of toluene in vapor phase =\frac{50}{94} =

= 0.53 (ans)

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