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vampirchik [111]
2 years ago
13

Please hurry ASAP One ride on a city bus costs $1.50. Martina has $18 on her bus pass. Write and solve an equation to find how m

any rides she can take without loading more money on her bus pass,
r= ?
She can ride the bus ? times before she needs to load more money on her pass.
Mathematics
2 answers:
bogdanovich [222]2 years ago
6 0

Answer:

She can ride the bus 12 times before she needs to load more money on  her pass.

Step-by-step explanation

1. You would take 18 and divide it by 1.5 (1.50) to get 12.

seraphim [82]2 years ago
4 0

Answer:

it,s 12

Step-by-step explanation:

you keep on minus 1.50 from 18 e.g. 17.50, 16, 15.50, 14, 13.50, 12

another e.g. 1.50[_18

                       = 12

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A toy manufacturer wants to know how many new toys children buy each year. A sample of 1492 children was taken to study their pu
julia-pushkina [17]

By assuming the standard deviation of population 2.2 the confidence interval is 8.67 toys,8.94 toys.

Given sample size of 1492 children,99% confidence interval , sample mean of 8.8, population standard deviation=2.2.

This type of problems can be solved through z test and in z test we have to first find the z score and then p value from normal distribution table.

First we have to find the value of α which can be calculated as  under:

α=(1-0.99)/2=0.005

p=1-0.005=0.995

corresponding z value will be 2.575 for p=0.995 .

Margin of error=z*x/d

where x is mean and d is standard deviation.

M=2.575*2.2/\sqrt{1492}

=0.14

So the lower value will be x-M

=8.8-0.14

=8.66

=8.67 ( after rounding)

The upper value will be x+M

=8.8+0.14

=8.94

Hence the confidence interval will be 8.67 toys and 8.94 toys.

Learn more about z test at brainly.com/question/14453510

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8 0
2 years ago
Find the slope <br> (-6,2) (4,5)
Misha Larkins [42]

Slope: 3/10

<u>Use the slope formula</u>

y_{2}-y_{1}/x_{2}-x_{1}\\5-2/4--6\\=3/10

<u>Note</u>

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3 0
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Read 2 more answers
Resolve into partial fractions<br><br>​
lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

1)

\frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A}{2 - x}  +  \frac{B}{x - 3}  \\  \\  \therefore \:  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)}   \\  \\ \therefore \:  11 + x = Ax - 3A + 2B - Bx \\  \\  \therefore \: 11 + x = - 3A  + 2B  + Ax -  Bx\\  \\  \therefore \: 11 + x = - 3A  + 2B  + (A - B)x \\  \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\  \therefore \: A  =  B  +  1.....(1) \\  \\  -  3A  + 2B = 11....(2) \\  from \: eq \: (1) \: and \: (2) \\  - 3(B  +  1) + + 2B = 11 \\  \\ - 3B   - 3  + 2B = 11 \\  \\  - B = 11 + 3 \\  \\ B =  - 14  \\ A  =   - 14 +  1 =  - 13 \\  \\  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{ - 13}{2 - x}  +  \frac{ - 14}{x - 3} \\  \\ \frac{11 + x}{(2 - x)(x - 3)}  = -   \frac{ 13}{2 - x}   -  \frac{ 14}{x - 3}

2)

\frac{12x + 11}{x^2 +x - 6}

=\frac{12x + 11}{x^2 +3x-2x - 6}

=\frac{12x + 11}{x(x +3) -2(x +3)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A}{(x +3)}+\frac{B}{(x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A(x-2)+B(x+3)}{(x-2)(x+3)}

\therefore 12x + 11 = A(x-2)+B(x+3)

\therefore 12x + 11 = Ax-2A+Bx+3B

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Equating like terms on both sides:

A + B = 12\implies A = 12-B... (1)

- 2A + 3B = 11... (2)

Solving equations (1) & (2), we find:

A = 5, B = 7

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{5}{(x +3)}+\frac{7}{(x - 2)}

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Answer:

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1 + 10 = 11

8 0
2 years ago
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