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kupik [55]
2 years ago
15

Can somone please help with delta math??

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
5 0

Answer:

yea sure

Step-by-step explanation:

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A spring has a natural length of 7 m. If a 4-N force is required to keep it stretched to a length of 11 m, how much work W is re
bezimeni [28]

Answer:

18 J is the work required to stretch a spring from 7 m to 13 m.

Step-by-step explanation:

The work done is defined to be the product of the force F and the distance d  that the object moves:

W=Fd

If F is measured in newtons and d<em> </em>in meters, then the unit for is a newton-meter, which is called a joule (J).

This definition work as long as the force is constant, but if the force is variable like in this case, we have that the work done is given by

W=\int\limits^b_a {f(x)} \, dx

Hooke’s Law states that the force required to maintain a spring stretched x    units beyond its natural length is proportional to

f(x)=kx

where k is a positive constant (called the spring constant).

To find how much work W is required to stretch it from 7 m to 13 m you must:

Step 1: Find the spring constant

We know that the spring has a natural length of 7 m and a 4 N force is required to keep it stretched to a length of 11 m. So, applying Hooke’s Law

4=k(11-7)\\\\\frac{k\left(11-7\right)}{4}=\frac{4}{4}\\\\k=1

Thus F=x

Step 2: Find the the work done in stretching the spring from 7 m to 13 m.

Recall that the natural length is 7 m, so when we stretch the spring from 7 m to 13 m, we are stretching it by 6 m beyond its natural length.

Work needed to stretch it by 6 m beyond its natural length

W=\int\limits^6_0 {x} \, dx \\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1\\\\\left[\frac{x^{1+1}}{1+1}\right]^6_0\\\\\left[\frac{x^2}{2}\right]^6_0=18

18 J is the work required to stretch a spring from 7 m to 13 m.

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3 years ago
The International Space Station orbits Earth at an altitude of 240 miles. If a camera were set up on the Space Station, how far
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<span>The International Space Station orbits Earth at an altitude of 240 miles. If a camera were set up on the Space Station,  Earth's horizon will be seen by the camera in a distance of </span><span>A. 480.31 miles.</span>
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3 years ago
Help asap !<br><br> -100x - 100 = 0<br> -100x = ?<br> x = ?
marin [14]

Answer:

-100x = 10 x = 1

Step-by-step explanation:

I did the math and this is what I got

6 0
3 years ago
Is the order pair (-5,9) a solution to the equation y = 5x -4
s2008m [1.1K]

Answer:

No

Step-by-step explanation:

9=5(-5)-4 is not correct, 5(-5)-4 is actually -29 so no, the coordinates are not a solution to the equation.

8 0
3 years ago
Read 2 more answers
Find the value g(-2), where g is defined below.<br> g(x) = 2x^2- 4x – 4
DanielleElmas [232]

Answer:

12

Step-by-step explanation:

For this question, simply plug in -2 for x:

g(-2)=2(-2)^2-4(-2)-4\\g(-2)=2(4)+8-4\\g(-2)=8+8-4\\g(-2)=12

Hope this helps!!

8 0
3 years ago
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