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3 years ago

Find the value of a and b

Mathematics

1 answer:

Luba_88 [7]3 years ago

3 0

Answer:

a = 60

b = 60

Step-by-step explanation:

We know that BC is 90°, because of the square thingy.

YB is 30°.

Now we do 180 - 30 - 90 = 60 (180 is the straight angle)

60 = b

Then a is the same.

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What is the volume of this triangular prism? 313.6cm3 506.8cm3 5,676.16cm3 11,352.32cm3

lyudmila [28]

The question is incomplete. Here is the complete question:

What is the volume of this triangular prism?

Base length = 22.4 cm

Height = 18.1 cm

Length = 28 cm

A) 313.6 cm3

B) 506.8 cm3

C) 5,676.16 cm3

D) 11,352.32 cm3

Answer:

$V=5,676.16\ cm^3$

Step-by-step explanation:

Given:

The base of the prism is triangular with base length equal to 22.4 cm and height 18.1 cm. The length of the prism is 28 cm.

The volume of a triangular prism is defined by the formula:

$V=(Area\ of\ base)\times (length)$

Here, the base is triangular and the area of a triangle is:

$A=\frac{1}{2}base \times height$

Therefore, the volume of the triangular prism is given as:

$V=\frac{1}{2}(base\times height\times length)$

Now, plug in the given values and solve for the volume 'V'.

$V=\frac{1}{2}(22.4\ cm\times 18.1\ cm\times 28\ cm)\\\\V=\frac{1}{2}(11,352.32\ cm^3)\\\\V=5,676.16\ cm^3$

Therefore, the correct answer is the third option.

$V=5,676.16\ cm^3$

7 0

3 years ago

Read 2 more answers

Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.

skad [1K]

Answer:

The absolute maximum and minimum is $20\; \text{and} -20.$

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

$f_x=y-4=0$

$f_y=x=0$

The only solution to this system of equations is the point (0, 4), which lies in the domain.

$f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1$

$\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1$

$\therefore (0,4)$ is a saddle point.

Boundary points - $(4,0), (-4,0), (0,16)$

Along boundary $y=16-x^2$

$f=x(16-x^2)-4x$

$=16x-x^3-4x$

$\Rightarrow f^'=16-3x^2-4=0$

$\Rightarrow 3x^2=12$

$\Rightarrow x=\pm2,\;\;y=14$

Values of f(x) at these points.

$\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}$

Therefore, the absolute maximum and minimum is $20\; \text{and} -20.$

6 0

3 years ago

A man who is 2 meters tall stands on level ground. He is 32 meters from the base of a tree. The angle of elevation of the top of

podryga [215]

Answer:

h = 16.92 m

Step-by-step explanation:

If you mean to man horizontal line of sight then the height of the tree is:

h = 2m + x

x is one right side and second is distance from the base of a tree 32m.

Tangence in this right triangle is:

tan 25° = x / 32 => x = 32 · tan 25° = 32 · 0.4663 = 14.92m

h = 2 + 14.92 = 16.92m

God with you!!!

6 0

3 years ago

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A large patio brick weighs 4 3/8 pounds. A small patio brick weighs 2 1/3 pounds. How much more does the large brick weigh?

Nikolay [14]

Subtracting the weight of the smaller brick from the larger gives us the weight difference:

4 3/8 lb - 2 1/3 lb. The two denominators are 8 and 3 respectively, resulting in an LCD of 24. Thus, our problem becomes:

4 9/24 - 2 8/24, which equals 2 1/24 lb. The weight difference is 2 1/24 lb.

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3 years ago

Please can you explain how you got the answers! Thanks

Sedbober [7]

First you have to find the measurement of the entire line,which will be equal x, than plug in in the equation between L and M

4 0

3 years ago

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