Question

how far from the lens is the image of the house if the house is 16 ft from the thin convex lens with a focal length of 8 ft

Answer 1

This question involves the concepts of the thin lens formula, focal length, and image distance.

The image of the house is "16 ft" away from the lens.

According to the thin lens formula:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where,

f = focal length = 8 ft

p = object distance = 16 ft

q = image distance = ?

Therefore,

$\frac{1}{8\ ft}=\frac{1}{16\ ft}+\frac{1}{q}\\\\\frac{1}{q}=\frac{1}{8\ ft}-\frac{1}{16\ ft}\\\\\frac{1}{q}=0.125\ ft^{-1}-0.0625\ ft^{-1}\\\\q=\frac{1}{0.0625\ ft^{-1}}$

q = 16 ft

Learn more about the thin lens formula here:

brainly.com/question/3074650