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adell [148]
3 years ago
7

When a chemical reaction occurs with only one substance, what happens to the atoms of that substance?

Physics
2 answers:
Bad White [126]3 years ago
7 0

Answer:when a chemical reaction occurs with only one substance, the atoms of that substance rearranges to form new bonds to make the products.

Explanation: During chemical reaction, the bonds between the reactants are broken and the atom bonds in new ways to form products that are chemically and physically different from the reactants.

Example is the breakdown reaction of hydrogen peroxide(the reactant) into water and oxygen( products). Here, 2 molecules of hydrogen peroxide is broken down to form 2 molecules of water and one molecule of oxygen. The atoms that started out in the hydrogen peroxide molecules are rearranged to form water molecules and oxygen molecules.

miskamm [114]3 years ago
6 0

Answer:

The atoms of the substance are rearranged

Explanation:

When a chemical reaction involves only one substance, the atoms of the reactant substance rearranges to yield the product substance(s).

Chemical bonds in the reactant substance are broken and new bonds are formed as the atoms in the reactant substance forms the product substance (s).

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True or False. The Magnitude of the induced voltage in a coil of wire depends on how quickly the magnetic flux through the coil
EleoNora [17]

Answer:

Yes, its true

Explanation:

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3 years ago
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Which is a more objective measurement, sound intensity or loudness, and why? 1. sound intensity is exactly same as loudness. 2.
fgiga [73]
The correct answer is:
<span>2. sound intensity is a more objective and physical attribute of a sound wave because loudness can vary from person to person

indeed, sound intensity is a measurable quantity, and so it is objective, while loudness is the subjective perception of the sound level, so it varies from person to person.</span>
7 0
3 years ago
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A wheel 1.0 m in radius rotates with an angular acceleration of 4.0rad/s2 . (a) If the wheel’s initial angular velocity is 2.0 r
Oliga [24]

Answer:

(a) ωf= 42 rad/s

(b) θ = 220 rad

(c) at = 4 m/s²  ,  v = 42 m/s

Explanation:

The uniformly accelerated circular movement,  is a circular path movement in which the angular acceleration is constant.

There is tangential acceleration (at ) and is constant.

We apply the equations of circular motion uniformly accelerated :

ωf= ω₀ + α*t  Formula (1)

θ=  ω₀*t + (1/2)*α*t²  Formula (2)

at = α*R  Formula (3)

v= ω*R  Formula (4)

Where:

θ : angle that the body has rotated in a given time interval (rad)

α : angular acceleration (rad/s²)

t : time interval (s)

ω₀ : initial angular velocity ( rad/s)

ωf: final angular velocity ( rad/s)

R : radius of the circular path (cm)

at : tangential acceleration (m/s²)

v : tangential speed (m/s)

Data

α = 4.0 rad/s² : wheel’s angular acceleration

t = 10 s

ω₀ = 2.0 rad/s  : wheel’s initial angular velocity

R = 1.0 m  : wheel’s radium

(a)  Wheel’s angular velocity after 10 s

We replace data in the formula (1):

ωf= ω₀ + α*t

ωf= 2 + (4)*(10)

ωf= 42 rad/s

(b) Angle that rotates the wheel in the 10 s interval

We replace data in the formula (2):

θ=  ω₀*t + (1/2)*α*t²

θ=  (2)*(10) + (1/2)*(4)*(10)²

θ=  220 rad  

θ=  220 rad  

(c) Tangential speed and acceleration of a point on the rim of the wheel at the end of the 10-s interval

We replace data in the Formula (3)

at = α*R = (4)(1)

at = 4 m/s²

We replace data in the Formula (4)

v= ω*R = (42)*(1)

v = 42 m/s

6 0
3 years ago
A tall, cylindrical chimney falls over when its base is ruptured. Treat the chimney as a thin rod of length 53.2 m. At the insta
rusak2 [61]
From an energy balance, we can use this formula to solve for the angular speed of the chimney

ω^2 = 3g / h sin θ

Substituting the given values:
ω^2 = 3 (9.81) / 53.2 sin 34.1
ω^2 = 0.987 /s

The formula for radial acceleration is:
a = rω^2

So,
a = 53.2 (0.987) = 52.494 /s^2

The linear velocity is:
v^2 = ar
v^2 = 52.949 (53.2) = 2816.887

The tangential acceleration is:
a = r v^2
a = 53.2 (2816.887)
a = 149858.378 m/s^2

If the tangential acceleration is equal to g:
g = r^2 3g / sin θ
Solving for θ
θ = 67° 
7 0
3 years ago
Calculate the wave number for the infrared absorption of D35Cl when there is a transition from v=0 to v=1 (Unit: cm^-1, 4-digit
AVprozaik [17]

Answer:

wave number = 0.3348 * 10⁻⁸ cm⁻¹

Explanation:

Given data:

K = 4.808 * 10^2 N/m

<u>Determine the wave number for the infrared absorption</u>

considering vibrational Spectre

k' =  2n / λ ---- ( 1 )

λ = c / v ----- ( 2 )

v = √k / u  --- ( 3 )

where : k' = wave number, λ = wavelength, c = velocity of light, v = frequency,  k = force constant, u = reduced mass

u = 1.90415 for  D35Cl

Input equations 2 and 3 into equation 1 to get the final equation

K' = 2n/c * √k / u

   = ( 2 * 3.14 ) / 2.98 * 10^8  ] * (√ 4.808 * 10^2 / 1.90415 )

   = 33.486 * 10⁻⁸ m⁻¹  ≈ 0.3348 * 10⁻⁸ cm⁻¹

6 0
3 years ago
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