11-2m-(n+5+(-m)-3n+8)
11-2m-n-5-m+3n-8
Answer: -2-3m+2n
To solve this, we use the z test.
The formula:
z = (x – u) / s
where x is sample value = 20, u is the mean = 15, and s is
the standard deviation = 2.5
z = (20 – 15) / 2.5
z = 2
Since we are looking for values greater than 20, this is
right tailed test. We use the standard distribution tables to find for P.
P = 0.0228
Therefore:
number of students = 100 * 0.0228 = 2.28
<span>2 to 3 students will get greater than 20 measurement</span>
This value is very different from the other values
1) cluster
2) outlier
3) association
4) trend line
5) scatter plot
