What is the solution to the system of equations?
1 answer:
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Answer:
Check below, please.
Step-by-step explanation:
Hi, there!
Since we can describe eccentricity as
a) Eccentricity close to 0
An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)
b) Eccentricity =5
An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:
c) Eccentricity close to 1
In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.
ANSWER
No solution
EXPLANATION
The first equation is
and the second equation is
We equate the two equations to obtain;
This implies that
There is no real number whose square is -1.
Therefore, the equation has no solution.