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Zanzabum
3 years ago
6

(x1,y1) is (-4,-2) and (x2,y2) is (2,4)

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

y = x+2

Step-by-step explanation:

(x1,y1) is (-4,-2) and (x2,y2) is (2,4)

Slope intercept form is y = mx+b

m = slope

b = add on

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Substitute numbers

Slope = \frac{4-(-2)}{2-(-4)}

Two negatives = one positive

Simplify

Slope = \frac{4+2}{2+4}=\frac{6}{6}=1

The slope is 1

We can substitute y, x, and the slope

4 = 2*1 + b

4 = 2+b

b = 2

Slope intercept form is y = mx+b

Answer is y = x+2

Hope this helps :)

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5.26%

Step-by-step explanation:

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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
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Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

The probability density of the volume of the cube

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For a uniform distribution, we have:

x \to U(a,b)

and

f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.

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(a,b) = (9,10)

So, we have:

f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

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Differentiate F(x) to give:

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So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

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