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pantera1 [17]
2 years ago
9

ST

Mathematics
2 answers:
lina2011 [118]2 years ago
7 0

Answer:

the probability would be 30% but as a fraction it would be 3/10

Step-by-step explanation:

zhenek [66]2 years ago
6 0

Answer:

7/15

Step-by-step explanation:

The probability of the first one is 7/10 and the second one is 6/9. Multiply them together and you get 42/90, which simplifies to 7/15.

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Yuki bought a pound of confetti for \$12$12. What is the price, in dollars, per ounce of confetti? There are 1616 ounces in 11 p
tatiyna

Answer:

$0.75

Step-by-step explanation:

We have been given that Yuki bought a pound of confetti for $12.

To find the price of per ounce of confetti, we will divide the total price of 1 pound confetti by number of ounces in 1 pound.

1 pound = 16 ounces.    

Let us divide 12 by 16 to find the price of confetti per ounce.

\text{Price of per ounce confetti}=\frac{12}{16}

\text{Price of per ounce confetti}=\frac{3}{4}

\text{Price of per ounce confetti}=0.75

Therefore, the price of per ounce confetti is $0.75.


3 0
4 years ago
Which statement describes the relationship, if any, that exists between triangle KLM and triangle NPQ? Triangle L K M. Side K L
Anettt [7]

Answer:

Its B I think

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The math department needs to buy new textbooks and laptops for the computer science classroom. The textbooks cost $116.00 each,
Oksana_A [137]

Answer:

6 laptops.

Step-by-step explanation:

$6500 is the budget. If each textbook costs $116, and 30 textbooks are needed, you multiply.

116 x 30 = 3480.

3480 was spent on the textbooks, and the rest needs to go into laptops.

6500 - 3480 = 3020.

Now to find out how many laptops can be bought with the remaining money, divide.

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6 0
4 years ago
In how many distinct ways can the letters of the word mathematics be arranged? (first, does the order matter?)
TEA [102]
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).

Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
4 0
3 years ago
Help me , i will give you points
vovangra [49]

Answer:

some advantages is that you can not pay all at once some disadvantage is that you can feel like you can. do that always then you can get late fees that can cost more the the product it self

3 0
3 years ago
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